表：Customer

select Power, 
UserName= stuff(
(
	select ',' + UserName
	from Customer t 
	where Power = t2.Power 
	for xml path('')
) , 1 , 1 , ''),
password= stuff(
(
	select ',' + password
	from Customer t 
	where Power = t2.Power 
	for xml path('')
) , 1 , 1 , '')
from Customer t2
group by Power

查詢結果：

【2】對於 ORACLE SQL，使用以下方法

SELECT 
CNAME,YEAR,
REPLACE(WMSYS.WM_CONCAT(ID), ',', ',') ID,
REPLACE(WMSYS.WM_CONCAT(birthday), ',', ',') birthday 
FROM tb_test 
GROUP BY CNAME,YEAR;