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String.split()分割字串,轉義字元

1、String.split()

String有個方法是分割字串  .split()。但是有寫字串是需要轉義才能分割,不然就會出錯。

需要轉義的字串:.  $  |   (   )  [   {   ^  ?  *  +  \\      共12個特殊字元,遇到以這些字元進行分割字串的時候,需要在這些特殊字元前加雙反斜槓 \\

例如:

str.split("\\.")

str.split("\\$")

str.split("\\|")  

str.split("\\(")  

str.split("\\)") 

str.split("\\[")

str.split("\\{")

str.split("\\^")

  

str.split("\\?")  

str.split("\\*") 

str.split("\\+")

str.split("\\\\")

2、原始碼:

public String[] split(String regex) {
        return split(regex, 0);
    }  
public String[] split(String regex, int limit) {
        /* fastpath if the regex is a
         (1)one-char String and this character is not one of the
            RegEx's meta characters ".$|()[{^?*+\\", or
         (2)two-char String and the first char is the backslash and
            the second is not the ascii digit or ascii letter.
         */
        char ch = 0;
        if (((regex.value.length == 1 &&
             ".$|()[{^?*+\\".indexOf(ch = regex.charAt(0)) == -1) |
| (regex.length() == 2 && regex.charAt(0) == '\\' && (((ch = regex.charAt(1))-'0')|('9'-ch)) < 0 && ((ch-'a')|('z'-ch)) < 0 && ((ch-'A')|('Z'-ch)) < 0)) && (ch < Character.MIN_HIGH_SURROGATE || ch > Character.MAX_LOW_SURROGATE)) { int off = 0; int next = 0; boolean limited = limit > 0; ArrayList<String> list = new ArrayList<>(); while ((next = indexOf(ch, off)) != -1) { if (!limited || list.size() < limit - 1) { list.add(substring(off, next)); off = next + 1; } else { // last one //assert (list.size() == limit - 1); list.add(substring(off, value.length)); off = value.length; break; } } // If no match was found, return this if (off == 0) return new String[]{this}; // Add remaining segment if (!limited || list.size() < limit) list.add(substring(off, value.length)); // Construct result int resultSize = list.size(); if (limit == 0) while (resultSize > 0 && list.get(resultSize - 1).length() == 0) resultSize--; String[] result = new String[resultSize]; return list.subList(0, resultSize).toArray(result); } return Pattern.compile(regex).split(this, limit); }