函式返回盡然能作為左值     函式引數裡的二級指標  函式引數裡的（資料型別引用） 經典不是優雅

#include <iostream>
#include <iomanip>
#include <stdio.h>
using namespace std;

struct CAssoc
{
	CAssoc* pNext;
	void* unused;
	void* value;
};
CAssoc *gpGloable=NULL;

void*& func(CAssoc **temp);

void main()
{
	func(&gpGloable)="ABCDEFGHIJKLMNOPQRST";

	cout<<(char*)gpGloable->value<<endl;
	printf("%s\n\n",gpGloable->value);

	//
	//////////////////////////////////////////////////////////////////////////
	unsigned int a=100;
	unsigned int *p=NULL;
	p=&a;
	unsigned int **q=NULL;
	q=&p;
	cout<<a<<"\t"<<*p<<"\t"<<p<<"\t"<<**(&p)<<endl;
	printf("%d\n\n",*p);

	//
	//////////////////////////////////////////////////////////////////////////
	CAssoc ss;
	ss.unused=&a;
	ss.value="FFFFFFFF";
	unsigned int xx=(unsigned int)(*&(ss.unused));
	cout<<hex<<setw(8)<<xx<<endl;
	cout<<(int*)(ss.unused)<<endl;
	printf("%d\n\n",*&(ss.unused));
	printf("rrrrrrr%d\n\n",((int*)(ss.unused)));
	cout<<(char*)ss.value<<endl;
	printf("%s\n\n",ss.value);
}

void*& func(CAssoc **temp)
{
	CAssoc *p=new CAssoc;
	*temp=p;
	return p->value;
}