Python3.7 Scrapy crawl 執行出錯 SyntaxError: invalid syntax 解決方法
阿新 • • 發佈:2019-02-02
錯誤如下:
。。。 File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/scrapy/utils/misc.py", line 44, in load_object mod = import_module(module) File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/importlib/__init__.py", line 127, in import_module return _bootstrap._gcd_import(name[level:], package, level) File "<frozen importlib._bootstrap>", line 1006, in _gcd_import File "<frozen importlib._bootstrap>", line 983, in _find_and_load File "<frozen importlib._bootstrap>", line 967, in _find_and_load_unlocked File "<frozen importlib._bootstrap>", line 677, in _load_unlocked File "<frozen importlib._bootstrap_external>", line 728, in exec_module File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/scrapy/extensions/telnet.py", line 12, in <module> from twisted.conch import manhole, telnet File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/twisted/conch/manhole.py", line 154 def write(self, data, async=False): ^ SyntaxError: invalid syntax
原因是python3.7中將async設為關鍵字。
解決辦法:
根據錯誤提示的路徑,找到manhole.py檔案。將檔案中async引數全部更改為其它名,比如async1即可。