[leetcode]-771. Jewels and Stones(C語言)
阿新 • • 發佈:2019-02-03
You're given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
"a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
int numJewelsInStones(char* J, char* S) {
int a[256]={0};
int i,j,k,sum=0;
int len1=strlen(S);
for(i=0;i<len1;i++)
a[S[i]]++;
int len2=strlen(J);
for(i=0;i<len2;i++)
sum+=a[J[i]];
return sum;
}