演算法-輸出英文字母對應的數字
阿新 • • 發佈:2019-02-03
問題描述:
如輸入數字a~z, 輸出數字1~26
輸入數字ab,輸出28
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class To26 {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
String src = ""; int target = 0 ;
while(input.hasNextLine()){
src = input.nextLine();
target = tranform(src);
}
}
public static int tranform(String str){
String[] nums = {"a", "b","c", "d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z" };
Map<String, Integer> numMap = new HashMap<String, Integer>(); int result = 0; int length = str.length();
if(str.length()<0 || "".equals(str)){
System.out.println("ERROR");
return -1;
}
for(int i = 0; i<nums.length; i++){
numMap.put(nums[i], i);
}
if (str.length()==1){
if(" ".equals(str)){
System.out.println("Error");
return -1;
}
//System.out.println("Error");
result = numMap.get(str) + 1;
}else{
int tempLength = length;
for(int i = 0; i < length; i++){
char ch = str.charAt(i);
int location = numMap.get(String.valueOf(ch));
result += (location + 1) * 26 * (tempLength - 1);
tempLength = tempLength - 1 ;
}
char ch = str.charAt(length-1);
int temp = numMap.get(String.valueOf(ch)) + 1;
//result = (length - 1)*26 + temp;
result = result + temp;
}
System.out.println(result);
return result;
}
}