#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>

using namespace std;

void PrintCharArray(string a);
bool CharContain(string src, string des);

int main(int argc, char *argv[])
{
	/*
	*  字串的移位包含問題：給定兩個字串s1和s2，要求判斷s2是否能夠被s1做迴圈移位(rotate)得到的字串包含。
	*  eg: s1 = AABCD, s2 = CDAA, 返回true; s1 = ABCD, s2 = ACBD, 返回false.
	*  注意s1迴圈移位所有可能包含於s1s1中，因此，可以用string的find方法判斷s1s1中是否包含s2.
	*/

	//string src = "AABBCD";
	//string des = "CDAA";
	//PrintCharArray(src);
	//PrintCharArray(des);
	//CharContain(src, des);

	clock_t start_time = clock();

	CharContain("AABBCD", "CDAA");
	CharContain("ABCD", "ACBD");

	clock_t end_time = clock();

	cout << "Running time of CharContain1 is " 
		<< static_cast<double>(end_time - start_time) / CLOCKS_PER_SEC * 1000
		<< "ms." << endl;
	
	return 0;
}

void PrintCharArray(string a)
{
	if (!a.empty())
	{
		int len = a.size();
		for (int i = 0; i < len; i++)
		{
			cout << a[i];
		}
	}
	cout << endl;
}

bool CharContain(string src, string des)
{
	int len = src.size();
	string tmp = src + src;

	int index = tmp.find(des);

	if (index != -1)
	{
		cout << "Case One: " << endl;
		for (int i = index; i < len * 2; i++)
		{
			cout << tmp[i];
		}
		cout << endl;
		cout << "s2 in s1s1." << endl << endl;
		return true;
	}
	else
	{
		cout << "Case Two: " << endl;
		cout << "s2 not in s1s1." << endl;
		return false;
	}
}