leetcode 495. Teemo Attacking
/** * 495. Teemo Attacking * @param timeseries * @param duration * @return * 2017年3月12日下午9:16:40 */ public int findPoisonedDuration(int[] timeSeries, int duration) { if (timeSeries.length == 0) return 0; int res = 0; for (int i = 1; i<timeSeries.length; i++) { int span = timeSeries[i] - timeSeries[i-1]; if (span > duration) res += duration; else res += span; } return res + duration; }
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leetcode 495. Teemo Attacking
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