反轉一個單鏈表。

示例:

輸入: 1->2->3->4->5->NULL
輸出: 5->4->3->2->1->NULL

進階:

你可以迭代或遞迴地反轉連結串列。你能否用兩種方法解決這道題？

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None


class Solution:
    def reverseList(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        if head == None or head.next == None:
            return head
        pre = None
        cur = head
        h = head
        while cur:
            h = cur
            tmp = cur.next
            cur.next = pre
            pre = cur
            cur = tmp
        return h