銀行排隊問題之單佇列多視窗加VIP服務
阿新 • • 發佈:2019-02-05
#include <bits/stdc++.h> using namespace std; typedef struct Window { int time; int num; }Winow; typedef struct Person { int atime, wtime, ntime, isvip; }Person; Winow win[15]; Person per[1010]; int N, K, vipwin, who_possess_vipwin = 0; int vipper[1010]; int vipnum = 0, curvippos = 0; int VipGetPos(Person p) { int pos, min_t = 100000; for(int i = 0; i < K; ++i) { if(p.atime >= win[i].time) { pos = i; break; } if(win[i].time < min_t) { min_t = win[i].time; pos = i; } } if(win[pos].time == win[vipwin].time || win[vipwin].time <= p.atime) pos = vipwin; if(pos == vipwin) who_possess_vipwin = 1; return pos; } int BeggarGetPos(Person p)//哈哈 惡搞一下蝦米音樂 { int pos, min_t, pos1, pos2, min_t1 = 100000, min_t2 = 100000; for(int i = 0; i < K; ++i) { if(p.atime > win[i].time) { pos1 = i; return pos1; } if(win[i].time < min_t1) { min_t2 = min_t1; pos2 = pos1; min_t1 = win[i].time; pos1 = i; } else { if(win[i].time < min_t2) { min_t2 = win[i].time; pos2 = i; } } } if(pos1 == vipwin) { //int flag; if(per[vipper[curvippos]].atime > win[pos1].time || vipnum == 0) pos1 = pos1; else pos1 = pos2; } pos = pos1; if(pos == vipwin) who_possess_vipwin = 0; return pos; } int main() { scanf("%d", &N); for(int i = 1; i <= N; ++i) { scanf("%d %d %d", &per[i].atime, &per[i].ntime, &per[i].isvip); if(per[i].ntime > 60) per[i].ntime = 60; if(per[i].isvip == 1) vipper[vipnum++] = i; } scanf("%d %d", &K, &vipwin); for(int i = 0; i < K; ++i) { win[i].time = 0; win[i].num = 0; } for(int i = 1; i <= N; ++i) { int winpos; if(per[i].isvip == 1) { winpos = VipGetPos(per[i]); curvippos++; } else { winpos = BeggarGetPos(per[i]); } // for(int j = 0; j < K; ++j) // printf("win[%d]的時間為 %d num為 %d\n", j, win[j].time, win[j].num); // printf("要處理的是%d到達時間為 %d 事物時間為%d", i, per[i].atime, per[i].ntime); // if(!per[i].isvip) // printf("不"); // cout << "是會員" << endl; // cout << "選擇視窗為" << winpos << endl; per[i].wtime = win[winpos].time - per[i].atime > 0?win[winpos].time - per[i].atime:0; win[winpos].time = per[i].ntime + per[i].atime + per[i].wtime; win[winpos].num++; } int sum = 0; int max_w = -1; int max_t = -1; for(int i = 1; i <= N; ++i) { //printf("id = %d wtime = %d\n", i, per[i].wtime); sum += per[i].wtime; if(max_w < per[i].wtime) max_w = per[i].wtime; } for(int i = 0; i < K; ++i) { if(win[i].time > max_t) max_t = win[i].time; } double ave = (sum * 1.0) / (N * 1.0); printf("%.1lf %d %d\n", ave, max_w, max_t); for(int i = 0; i < K; ++i) { if(i != 0) printf(" "); printf("%d", win[i].num); } }