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Python 列表-List

列表

  • 資料序列,儲存多個數據的連續空間

  • 下標從 0 開始,不可越界,可為負數(表示從後往前數)

  • a_list = [1, 'this', 'that', 3]
    b_list = list('hello')
    c_list = list(range(0, 10, 2))
    
    print(a_list[-1]) #輸出 3
    for x in c_list:
      print(x)
    for i in range (len(b_list)):
      print(b_list[i])
  • 順序查詢

    aList = [3, 3, 8, 8, 9, 3, 9, 1, 8, 0]
    print("8 第一次出現的位置是第 %d 個"
    %(aList.index(8)+1)) print(aList.index(8, 4, len(aList)) + 1) #從4到 len(aList)之間出現的第一個8的下標 print(aList.count(3)) #3出現的次數
  • 新增資料

    array = [1, 3, 9, 12, 0]
    array[4] = 20
    array.append(26)
    array.extend([27, 28, 29])
    array.insert(2, 6)
    for i in range(len(array)):
      print(array[i], end = ' ')
    
    #1 3 6 9 12 20 26 27 28 29
  • 刪除資料

    aList = [1, 9, 2, 7]
    aList.remove(2)
    for x in aList:
      print(x)
    
    #1 9 7
    

作業

  • grade = []
    for i in range(10):
      std_id = str(input('input student ID: '))
      score = float(input('input his/her score: '))
      grade.append([std_id, score])
    
    for i in range(len(grade)):
      print(grade[i][0], grade[i][1
    ], sep = '\t')
  • grade = [[201,77],[202,82],[203,93],[204,87],[205,88],[206,91]]
    find = int(input())
    flag = 0
    for i in range(len(grade)):
      if grade[i][0] == find :
          print(grade[i][1])
          flag = 1
          break
    if flag == 0 :
      print('not find')