Leetcode: 621. Task Scheduler
題目大意:
給定一些任務以及一個整數時隙n,26種從A~Z。CPU每個時隙可以處理一個任務,處理一個任務後需要經過n時隙後才能處理一個相同的任務,但是這n個時隙可以利用起來處理別的任務。給出最少時隙。
c++code:
class Solution {
public:
int leastInterval(vector<char>& tasks, int n) {
vector<int> Task(26, 0);
for (char task : tasks) {
++Task[task - 'A' ];
}
sort(Task.begin(), Task.end());
int i = 25, mx = Task[25], len = tasks.size();
while (i >= 0 && Task[i] == mx) --i;
return max(len, (mx - 1) * (n + 1) + 25 - i);
}
};
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