1. 程式人生 > >AngularJS中$http.post問題

AngularJS中$http.post問題

angularjs post跟jquery post完全兩回事,會在java getparamname函式取不到值

在專案到root module加上以下程式碼:

// Your app's root module...
angular.module('MyModule', [], function($httpProvider) {
  // Use x-www-form-urlencoded Content-Type
  $httpProvider.defaults.headers.post['Content-Type'] = 'application/x-www-form-urlencoded;charset=utf-8'
; /** * The workhorse; converts an object to x-www-form-urlencoded serialization. * @param {Object} obj * @return {String} */ var param = function(obj) { var query = '', name, value, fullSubName, subName, subValue, innerObj, i; for(name in obj) { value = obj[name]; if
(value instanceof Array) { for(i=0; i<value.length; ++i) { subValue = value[i]; fullSubName = name + '[' + i + ']'; innerObj = {}; innerObj[fullSubName] = subValue; query += param(innerObj) + '&'; } } else if(value instanceof
Object) { for(subName in value) { subValue = value[subName]; fullSubName = name + '[' + subName + ']'; innerObj = {}; innerObj[fullSubName] = subValue; query += param(innerObj) + '&'; } } else if(value !== undefined && value !== null) query += encodeURIComponent(name) + '=' + encodeURIComponent(value) + '&'; } return query.length ? query.substr(0, query.length - 1) : query; }; // Override $http service's default transformRequest $httpProvider.defaults.transformRequest = [function(data) { return angular.isObject(data) && String(data) !== '[object File]' ? param(data) : data; }]; });

原理是jquery的contentType 是

application/x-www-form-urlencoded

post的資料會轉換成name=123&title=123

angularjs是

application/json

同時資料是個json {name:”123”,title:”213”};
所以上面程式碼是改了這兩處。

這裡寫圖片描述