Java判斷IP在屬於ip段
阿新 • • 發佈:2019-02-12
問題是這樣的,輸入一個IP地址,先判斷一下該IP是否是合法的IP地址,然後再判斷該IP地址是否在一個相應的IP段內
開始IP為beginIp,結束問題是這樣的,輸入一個IP地址,先判斷一下該IP是否是合法的IP地址,然後再判斷該IP地址是否在一個相應的IP段內
public class ipTest { /** * 判斷IP是否在指定範圍; */ public static boolean ipIsValid(String ipSection, String ip) { if (ipSection == null) throw new NullPointerException("IP段不能為空!"); if (ip == null) throw new NullPointerException("IP不能為空!"); ipSection = ipSection.trim(); ip = ip.trim(); final String REGX_IP = "((25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)\\.){3}(25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)"; final String REGX_IPB = REGX_IP + "\\-" + REGX_IP; if (!ipSection.matches(REGX_IPB) || !ip.matches(REGX_IP)) return false; int idx = ipSection.indexOf('-'); String[] sips = ipSection.substring(0, idx).split("\\."); String[] sipe = ipSection.substring(idx + 1).split("\\."); String[] sipt = ip.split("\\."); long ips = 0L, ipe = 0L, ipt = 0L; for (int i = 0; i < 4; ++i) { ips = ips << 8 | Integer.parseInt(sips[i]); ipe = ipe << 8 | Integer.parseInt(sipe[i]); ipt = ipt << 8 | Integer.parseInt(sipt[i]); } if (ips > ipe) { long t = ips; ips = ipe; ipe = t; } return ips <= ipt && ipt <= ipe; } public static void main(String[] args) { if (ipIsValid("192.168.1.1-192.168.1.10", "192.168.3.54")) { System.out.println("ip屬於該網段"); } else System.out.println("ip不屬於該網段"); } }