程式設計師面試寶典中，大家應該都看過各種排序方法：

   冒泡

   選擇

   插入

   快速

   堆排序

   等等..

  這些針對的都是簡單的資料型別，比如數值型int型別，當遇到實際情況中的複雜排序，比如對一個公司的員工，依據姓名，年齡，性別等不同的因素綜合排序的情形，用上面的排序方法，將無法實現。但是不要害怕～java中有大神器：Comparator介面

  我們來看下原始碼，簡單的讓你不知道該怎麼做..

public interface Comparator<T> {
    /**
     * Compares its two arguments for order.  Returns a negative integer,
     * zero, or a positive integer as the first argument is less than, equal
     * to, or greater than the second.<p>
     *
     * In the foregoing description, the notation
     * <tt>sgn(</tt><i>expression</i><tt>)</tt> designates the mathematical
     * <i>signum</i> function, which is defined to return one of <tt>-1</tt>,
     * <tt>0</tt>, or <tt>1</tt> according to whether the value of
     * <i>expression</i> is negative, zero or positive.<p>
     *
     * The implementor must ensure that <tt>sgn(compare(x, y)) ==
     * -sgn(compare(y, x))</tt> for all <tt>x</tt> and <tt>y</tt>.  (This
     * implies that <tt>compare(x, y)</tt> must throw an exception if and only
     * if <tt>compare(y, x)</tt> throws an exception.)<p>
     *
     * The implementor must also ensure that the relation is transitive:
     * <tt>((compare(x, y)>0) && (compare(y, z)>0))</tt> implies
     * <tt>compare(x, z)>0</tt>.<p>
     *
     * Finally, the implementor must ensure that <tt>compare(x, y)==0</tt>
     * implies that <tt>sgn(compare(x, z))==sgn(compare(y, z))</tt> for all
     * <tt>z</tt>.<p>
     *
     * It is generally the case, but <i>not</i> strictly required that
     * <tt>(compare(x, y)==0) == (x.equals(y))</tt>.  Generally speaking,
     * any comparator that violates this condition should clearly indicate
     * this fact.  The recommended language is "Note: this comparator
     * imposes orderings that are inconsistent with equals."
     *
     * @param o1 the first object to be compared.
     * @param o2 the second object to be compared.
     * @return a negative integer, zero, or a positive integer as the
     *         first argument is less than, equal to, or greater than the
     *         second.
     * @throws NullPointerException if an argument is null and this
     *         comparator does not permit null arguments
     * @throws ClassCastException if the arguments' types prevent them from
     *         being compared by this comparator.
     */
  <span style="font-size:18px;">  int compare(T o1, T o2);</span>

    /**
     * Indicates whether some other object is "equal to" this
     * comparator.  This method must obey the general contract of
     * {@link Object#equals(Object)}.  Additionally, this method can return
     * <tt>true</tt> <i>only</i> if the specified object is also a comparator
     * and it imposes the same ordering as this comparator.  Thus,
     * <code>comp1.equals(comp2)</code> implies that <tt>sgn(comp1.compare(o1,
     * o2))==sgn(comp2.compare(o1, o2))</tt> for every object reference
     * <tt>o1</tt> and <tt>o2</tt>.<p>
     *
     * Note that it is <i>always</i> safe <i>not</i> to override
     * <tt>Object.equals(Object)</tt>.  However, overriding this method may,
     * in some cases, improve performance by allowing programs to determine
     * that two distinct comparators impose the same order.
     *
     * @param   obj   the reference object with which to compare.
     * @return  <code>true</code> only if the specified object is also
     *          a comparator and it imposes the same ordering as this
     *          comparator.
     * @see Object#equals(Object)
     * @see Object#hashCode()
     */
<span style="font-size:18px;">    boolean equals(Object obj);</span>
}
 
 

  具體程式碼如下：

package someTest;

import java.util.Comparator;

class Person {  
	
String firstname,lastname;  
Boolean sex;  
Integer age;  

public Person(String firstname,String lastname,Boolean sex,Integer age) {  
    this.firstname = firstname;  
    this.lastname = lastname;  
    this.sex = sex;  
    this.age = age;  
}  
public String getFirstName() {  
     return firstname;  
   }  
  
   public String getLastName() {  
     return lastname;  
   }  
   public Boolean getSex() {  
      return sex;  
    }  
  
    public Integer getAge() {  
      return age;  
    }  
  
//為了輸入方便，重寫了toString()  
public String toString()  
    {  
      return firstname +" "+lastname+" "+(sex.booleanValue()?"男":"女")+" "+age;  
    }  
}  
//end person  
 
public class CompareObject implements Comparator<Object> {
@Override
public int compare(Object o1, Object o2){  
	        if (o1 instanceof String) {  
	          
	        	return compareImp( (String) o1, (String) o2);  
	          
	        }else if (o1 instanceof Integer) {  
	        	
	          return compareImp( (Integer) o1, (Integer) o2);  
	          
	        }else if (o1 instanceof Boolean) {  
	        	
	        return compareImp( (Boolean) o1, (Boolean) o2);  
	        
	        } else if (o1 instanceof Person) {  
	        	
	        return compareImp( (Person) o1, (Person) o2);  
	        
	        }else {  //根據需要擴充套件compare函式
	          System.err.println("未找到合適的比較器");  
	          return 1;  
	        }  
	      }  
	//過載  
  public int compareImp(String o1, String o2) {  
	        String s1 = (String) o1;  
	        String s2 = (String) o2;  
	        int len1 = s1.length();  
	        int len2 = s2.length();  
	        int n = Math.min(len1, len2);  
	        char v1[] = s1.toCharArray();  
	        char v2[] = s2.toCharArray();  
	        int pos = 0;  
	  
	        while (n-- != 0) {  
	          char c1 = v1[pos];  
	          char c2 = v2[pos];  
	          if (c1 != c2) {  
	            return c1 - c2;  
	          }  
	          pos++;  
	        }  
	        return len1 - len2;  
	      }  
	//過載  
 public int compareImp(Integer o1, Integer o2) {  
	        int val1 = o1.intValue();  
	        int val2 = o2.intValue();  
	        return (val1 < val2 ? -1 : (val1 == val2 ? 0 : 1));  
	  
	      }
 	//過載 
 public int compareImp(Boolean o1, Boolean o2) {  
	      return (o1.equals(o2)? 0 : (o1.booleanValue()==true?1:-1));  
	     }  
	  
 /*實體類的排序
  * 進行姓排序，誰的姓拼音靠前，誰就排前面。
  * 然後對名字進行排序。如果同名，女性排前頭。
  * 如果名字和性別都相同，年齡小的排前頭。
  * */
 //過載
public int compareImp(Person o1, Person o2) {  
	
	        String firstname1 = o1.getFirstName();  
	        String firstname2 = o2.getFirstName(); 
	        
	        String lastname1 = o1.getLastName();  
	        String lastname2 = o2.getLastName();  
	        
	        Boolean sex1 = o1.getSex();  
	        Boolean sex2 = o2.getSex();  
	        
	        Integer age1 = o1.getAge();  
	        Integer age2 = o2.getAge();  
	        
	        int compareFirstName = compare(firstname1, firstname2);
	        int compareLastName = compare(lastname1, lastname2);
	        int compareSex = compare(sex1, sex2);

	        if (compareFirstName != 0) {
	            return compareFirstName;
	        }

	        if (compareLastName != 0) {
	            return compareLastName;
	        }

	        if (compareSex != 0) {
	            return compareSex;
	        }

	        return compare(age1, age2);  
	  
	 } 
/*public boolean equals(Object obj){
	return true;
}*/
	public static void main(String[] args) {
		  Person[] person = new Person[] {  
			         new Person("zhangsan", "gg", Boolean.TRUE, new Integer(27)),  
			         new Person("lisi", "mm", Boolean.TRUE, new Integer(27)),  
			         new Person("wangwu", "mm", Boolean.FALSE, new Integer(27)),  
			         new Person("wangwu", "mm", Boolean.FALSE, new Integer(10)) 
			     };  
			     for (int i = 0; i < person.length; i++) {
			    	 if(i==0)
			    		 System.out.println("排序前：");
			       System.out.println("before sort=" + person[i]);  
			     }  
			     java.util.Arrays.sort(person, new CompareObject());  
			     for (int i = 0; i < person.length; i++) {  
			    	 if(i==0)
			    		 System.out.println("排序後：");
			        System.out.println("after sort=" + person[i]);  
			     } 
	}
}
 

排序前：
before sort=zhangsan gg 男 27
before sort=lisi mm 男 27
before sort=wangwu mm 女 27
before sort=wangwu mm 女 10
排序後：
after sort=lisi mm 男 27
after sort=wangwu mm 女 10
after sort=wangwu mm 女 27
after sort=zhangsan gg 男 27

 注：在實現Comparator介面時，並沒有實現equals方法，可程式並沒有報錯，原因是實現該介面的類也是Object類的子類，而Object類已經實現了equals方法