Problem Description

There are N table tennis, and only one of them has quality problem which is lighter than a normal ball. Give you a balance without any weights, calculate the minimum number of times that you can guarantee to find the bad one.

Input

Multiple cases. Each case is a single integer n (1<=n<=1000).

Output

the minimum number of times that you can guarantee to find the bad one.

Sample Input

2
6

Sample Output

1
2

#include <iostream>
using namespace std;
int f[1002];
int main()
{
	f[0]=0;
	f[1]=0;
	f[2]=1;
	f[3]=1;
	for(int i=4;i<=1000;i++)
	{
		if((i/3)*3<i)
		{
			f[i]=f[i/3+1]+1;
		}
		else f[i]=f[i/3]+1;
	}
	int a;
	while(scanf("%d",&a)!=EOF)
	{
		cout<<f[a]<<endl;
	}
	return 0;

}