A + B

Problem Description 讀入兩個小於100的正整數A和B,計算A+B.
需要注意的是:A和B的每一位數字由對應的英文單詞給出.

Input 測試輸入包含若干測試用例,每個測試用例佔一行,格式為"A + B =",相鄰兩字串有一個空格間隔.當A和B同時為0時輸入結束,相應的結果不要輸出. 

Output 對每個測試用例輸出1行,即A+B的值.

Sample Input one + two = three four + five six = zero seven + eight nine = zero + zero =
Sample Output 3 90 96
Source
Recommend JGShining 程式碼如下：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int covert(char s[])
{ 
 if(!strcmp(s,"zero")) return 0;
 else if(!strcmp(s,"one")) return 1;
 else if(!strcmp(s,"two")) return 2;
 else if(!strcmp(s,"three")) return 3;
 else if(!strcmp(s,"four")) return 4;
 else if(!strcmp(s,"five")) return 5;
 else if(!strcmp(s,"six")) return 6;
 else if(!strcmp(s,"seven")) return 7;
 else if(!strcmp(s,"eight")) return 8;
 else if(!strcmp(s,"nine")) return 9;
 return 0;
}
int main()
{
 int a,b;
 char s[6];
 while(1)
 {
  for(a=0,scanf("%s",s);s[0]!='+';scanf("%s",s))
   a=a*10+covert(s);
  for(b=0,scanf("%s",s);s[0]!='=';scanf("%s",s))
   b=b*10+covert(s);
  if(a+b==0) return 0;
  printf("%d\n",a+b);
 }
 system("pause");
 return 0;
}