countByKey

def countByKey(): Map[K, Long]
以RDD{(1, 2),(2,4),(2,5), (3, 4),(3,5), (3, 6)}為例 rdd.countByKey會返回{(1,1),(2,2),(3,3)}
scala例子

scala> val rdd = sc.parallelize(Array((1, 2),(2,4),(2,5), (3, 4),(3,5), (3, 6)))

scala> val countbyKeyRDD = rdd.countByKey()
countbyKeyRDD: scala.collection.Map[Int,Long] = Map(1
 
 -> 1, 2 -> 2, 3 -> 3)

java例子

    JavaRDD<Tuple2<Integer, Integer>> tupleRDD =
            sc.parallelize(Arrays.asList(new Tuple2<>(1, 2),
            new Tuple2<>(2, 4),
            new Tuple2<>(2, 5),
            new Tuple2<>(3, 4),
            new
 
 Tuple2<>(3, 5),
            new Tuple2<>(3, 6)));
    JavaPairRDD<Integer, Integer> mapRDD = JavaPairRDD.fromJavaRDD(tupleRDD);
    //countByKey
    Map<Integer, Object> countByKeyRDD = mapRDD.countByKey();
    for (Integer i:countByKeyRDD.keySet()) {
        System.out.println("("
 
+i+", "+countByKeyRDD.get(i)+")");
    }
/*
輸出  
(1, 1)
(3, 3)
(2, 2)

*/

collectAsMap

將pair型別(鍵值對型別)的RDD轉換成map, 還是上面的例子

scala例子

    scala> val rdd = sc.parallelize(Array((1, 2),(2,4),(2,5), (3, 4),(3,5), (3, 6)))

    scala> rdd.collectAsMap()
    res1: scala.collection.Map[Int,Int] = Map(2 -> 5, 1 -> 2, 3 -> 6)

java例子

    JavaRDD<Tuple2<Integer, Integer>> tupleRDD =
            sc.parallelize(Arrays.asList(new Tuple2<>(1, 2),
            new Tuple2<>(2, 4),
            new Tuple2<>(2, 5),
            new Tuple2<>(3, 4),
            new Tuple2<>(3, 5),
            new Tuple2<>(3, 6)));
    JavaPairRDD<Integer, Integer> mapRDD = JavaPairRDD.fromJavaRDD(tupleRDD);

    Map<Integer, Integer> collectMap = mapRDD.collectAsMap();