具體請參照http://stackoverflow.com/questions/8485239/java-rmi-connect-exception-connection-refused-to-host-timeout

RMI開發時出現這種錯誤時，可採用如下方式解決：

This RMI tutorial explains:

Before starting the compute engine, you need to start the RMI registry. The RMI registry is a simple server-side bootstrap naming facility that enables remote clients to obtain a reference to an initial remote object.

By default, the registry runs on port 1099, like yours. As the tutorial reports, just open a command prompt (on Windows) or a shell terminal (on a UNIX-like OS) and type:

For Windows (use javaw if start is not available):

start rmiregistry

Solaris OS or Linux:

rmiregistry &

UPDATE

I noticed, following the Oracle's tutorial and a my project of time ago, that in the Server

Controle obj =newControle(4);Registry reg =LocateRegistry.createRegistry(1099);System.out.println("Server is ready");
reg.rebind("CtrlServ", obj);

to:

Controle obj =newControle(4);Controle stub =(Controle)UnicastRemoteObject
 
.exportObject(obj,0);Registry reg =LocateRegistry.createRegistry(1099);System.out.println("Server is ready");
reg.rebind("CtrlServ", stub);

Because the tutorial reports:

The static UnicastRemoteObject.exportObject method exports the supplied remote object so that it can receive invocations of its remote methods from remote clients.

Also, if you are using the same host for a RMI invocation, it isn't needed in the Client class:

Registry registry =LocateRegistry.getRegistry("localhost");

Simply invoke:

Registry registry =LocateRegistry.getRegistry();

Because Oracle reports:

The no-argument overload of LocateRegistry.getRegistry synthesizes a reference to a registry on the local host and on the default registry port, 1099. You must use an overload that has an int parameter if the registry is created on a port other than 1099.