用sql語句實現年齡分段統計
阿新 • • 發佈:2019-02-18
SELECT
CASE
WHEN (age >= 10 AND age <= 20) THEN
'10-20'
WHEN (age >= 21 AND age <= 30) THEN
'21-30'
ELSE
'30-'
END 'eag_layer',
count(*) emps
FROM
address_book
GROUP BY
CASE
WHEN (age >= 10 AND age <= 20) THEN
'10-20'
WHEN (age >= 21 AND age <= 30) THEN
'21-30'
ELSE
'30-'
END
ORDER BY
1;
SELECT '10-20' 年齡段, COUNT(*) 人數
FROM [Table]
WHERE [年齡] BETWEEN 10 AND 20
UNION ALL
SELECT '21-30' 年齡段, COUNT(*) 人數
FROM [Table]
WHERE [年齡] BETWEEN 21 AND 30
UNION ALL
SELECT '31' 年齡段, COUNT(*) 人數
FROM [Table]
WHERE [年齡] > 30
select case when [年齡] BETWEEN 10 AND 20 then '10-20'
when [年齡] BETWEEN 20 AND 30 then '20-30'
when [年齡] > 30 then '30以上' end as '年齡段',
count(*) as '人數' FROM [Table]
先將年齡除10取整
select floor(年齡/10) as age from 表
再根據年齡整數分組統計
select age ,count(age) from
(
select floor(年齡/10) as age from 表
)
group by age
這樣基本效果就出來了,達到樓主的要求就要加如函式計算了
sql語法
select convert(varchar,age*10)+'--'+convert(varchar,(age+1)*10) ,count(age) from
(
select floor(年齡/10) as age from 表
)
group by age
oracle語法
select age*10 || '--'|| (age+1)*10 ,count(age) from
(
select floor(年齡/10) as age from 表
)
group by age