1. 程式人生 > >c++多態多實例

c++多態多實例

區域 color main include memset virt 兼容 函數 char

#include <bits/stdc++.h>
using namespace std;
class A
{
public:
    A()
    {
        cout << "構造A" << endl;
        s = new char[20];
        memset(s, 0, 20);
        strcpy(s, "hahaha");
    }
    virtual ~A()
    {
        cout << "析構A" << endl;
        
delete []s; } virtual void print() { cout << s << endl; } private: char *s; }; class B : public A { public: B() { cout << "構造B" << endl; s = new char[20]; memset(s, 0, 20); strcpy(s, "BBBBB"); } virtual
~B() { cout << "析構B" << endl; delete []s; } virtual void print() { cout << s << endl; } private: char *s; }; void ok(A *obj) { obj->print(); } void okk(A obj) { obj.print(); }

1.

int main()
{
    B 
*b = new B; A *obj = b; obj->print(); delete b; /*構造A 構造B BBBBB 析構B 析構A*/ }

2.

int main()
{
    B *b = new B;
    A *obj = b;
    obj->print();
    delete obj;

    /*構造A
    構造B
    BBBBB
    析構A*/
}

3.

int main()
{
    B b;
    A a = b;
    A *pa = &b;
    a.print();//這裏的a就是一個A類型的變量,它的內存布局在賦值的時候已經從B轉換到A了,多於的數據都被丟棄,因此其就是一個A類型的變量。
    pa->print();//其是一個指針,其類型雖然是A,但指向的區域的內容卻是一個B類型的內存結構,雖然內存結果的布局與A兼容,但其虛函數表中的Test卻是B的實現

    /*構造A
    構造B
    hahaha
    BBBBB
    析構A
    析構B
    析構A*/
}

4.

int main()
{
    B *b = new B;
    ok(b);

    /*構造A
    構造B
    BBBBB*/
}

5.

int main()
{
    B *b = new B;
    ok(b);
    delete b;
    
    /*構造A
    構造B
    BBBBB
    析構B
    析構A*/
}

6.

int main()
{
    B b;
    okk(b);

    /*構造A
    構造B
    hahaha
    析構A
    析構B
    析構A*/
}

7.

int main()
{
    B *b = new B;
    A a;
    b = &a; //報錯,不能讓子類指針指向父對象
    ok(b);
}

c++多態多實例