1、獲取xml樹

import xml.etree.ElementTree as ET


def getTree(xmlName):
  xmlName = xmlName.strip()
  try:
    tree = ET.parse(xmlName)
  except:
    tree = None
    print 'Analysis xml file fail,file name: {}'.format(xmlName)
  return tree

2、獲取根節點

def getRoot(tree):
  if tree is not None:
    root = tree.getroot()
  else:
    root = None
    print 'Get root fail'
  return root

3、檢視根節點

def seeRoot(root):
  '''<country name="tan">我是小明</country>'''
  if root is not None:
    print 'root tag:',root.tag # 標籤（country）
    print 'root attrib:',root.attrib # 屬性（name="tan"）
    print 'root text:',root.text # 文字（我是小明）
    print 'root tail:',root.tail # 尾字串（未涉及）

4、從根開始遍歷樹

def traverseRoot(root):
  if root is not None:
    for label1 in root:
      print 'label1 tag:',label1.tag
      print 'label1 attrib:',label1.attrib
      print 'label1 text:',label1.text
      print 'label1 tail:',label1.tail
      print '=================='
      for label2 in label1:
        print 'label2 tag:',label2.tag
        print 'label2 attrib:',label2.attrib
        print 'label2 text:',label2.text
        print 'label2 tail:',label2.tail
        print '=================='
        for label3 in label2:
          print 'label3 tag:',label3.tag
          print 'label3 attrib:',label3.attrib
          print 'label3 text:',label3.text
          print 'label3 tail:',label3.tail
          print '=================='

5、找到2012年的gdppc和neighbor下的b標籤（找到同層有條件的同層另一個tag的文字）

def findYouNedd(root):
  '''查詢year為2012下的b標籤的文字'''
  if root is not None:
    for label1 in root:
      for label2 in label1:
        if label1.tag == 'country' and label2.text == '2012': # 找到本層標籤為country且下一層有2012文字
          print 'Find tag為country and next year=2012'
          for child in label1:
            if child.tag == 'gdppc':
              print child.text
            for youNeed in child:
              if youNeed.tag == 'b':
                print 'You need:',youNeed.text

6、查詢父節點下的子節點

def findChildNode(fatherNode,childNode):
  childNode = childNode.strip()
  if fatherNode is not None:
    childs = fatherNode.findall(childNode)
    print childs
    print len(childs)

7、另一種辦法實現第4點

def findYouNedd2(root):
  countryNodes = root.findall('country')
  if root is not None:
    for countryNode in countryNodes:
      if countryNode.find('year').text == '2012':
        print countryNode.find('gdppc').text

8、移除節點

def delNode(tree,nodeName):
  nodeName = nodeName.strip()
  if tree is not None:
    root = tree.getroot()
    findNode = root.find(nodeName)
    if findNode is not None and findNode.tag == nodeName:
      root.remove(findNode)
  tree.write('removeNode.xml') # 移除節點後新的xml

9、xml樣例（xmlDemo.xml）

<?xml version="1.0"?>
<data>
  <country name="Liechtenstein">
    <rank>1</rank>
    <year>2008</year>
    <gdppc>141100</gdppc>
    <neighbor name="Austria" direction="E"/>
    <neighbor name="Switzerland" direction="W"/>
  </country>
  <country name="Singapore">
    <rank>4</rank>
    <year>2011</year>
    <gdppc>59900</gdppc>
    <neighbor name="Malaysia" direction="N">123
      <a name="a"> aaa </a>
    </neighbor>
  </country>
  <country name="Singapore">
    <rank>68</rank>
    <year>2012</year>
    <gdppc>13600</gdppc>
    <neighbor name="Costa Rica" direction="W"/>
    <neighbor name="Colombia" direction="E">456
      <b name="b"> bbb 
    </neighbor>
  </country>
  <city>789</city>
</data>

以上就是Python 解析xml檔案的示例的詳細內容，更多關於Python 解析xml的資料請關注我們其它相關文章！