python 解析xml檔案
阿新 • • 發佈:2020-07-15
https://www.cnblogs.com/handsome1013/p/10058838.html
ET.Parser 用法
https://www.cnblogs.com/yezuhui/p/6853323.html
import xml.etree.ElementTree as ET----------匯入xml模組
root = ET.parse('GHO.xml')------------------分析指定xml檔案
tree = root.getroot()-----------------------獲取第一標籤
data = tree.find('Data')--------------------查詢第一標籤中'Data'標籤
for item in obs:------------------------歷遍'Data'中的'obs'標籤下的所有標籤
key = item.attrib()-----------------提取key值引數
print(list(key))--------------------輸出key值
如何讀取屬性及節點內容。
怎樣將data中的 id,name及其值取出來?
問題解釋
兩種方式:
1.先取得node
String strID = node.getAttributes().getNamedItem("id").getNodeValue();
2.先取得element
String strID = element.getAttribute("id");
String strName = element.getAttribute("name");
小練習
#!/usr/bin/env python import sys import xml.etree.ElementTree as ET tree = ET.parse('abcdefg.xml') root = tree.getroot() iter_elem = root.findall('.//*') print(len(iter_elem)) #elem = root.find('') #print iter_elem for element in iter_elem: if element is None: continue if element.text is None: continue print("hello") context=[] src_elem = element.find("source") if src_elem is None: continue context.append(src_elem.text) print( "attri :%s"%src_elem.attrib) print("tag :%s"%src_elem.tag) #for item in src_elem: # key = item.text() # print list(key)