1. 程式人生 > 實用技巧 >python3 順時針列印矩陣元素

python3 順時針列印矩陣元素

code

'''
輸入一個矩陣,按照從外向裡以順時針的順序依次打印出每一個數字,
例如,如果輸入如下矩陣:
[[ 1,  2,  3,  4],
 [ 5,  6,  7,  8],
 [ 9, 10, 11, 12],
 [13, 14, 15, 16]]
則依次打印出數字 1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.
'''

# -*- coding:utf-8 -*-
class Solution:
    # matrix型別為二維列表,需要返回列表
    def printMatrix(self, matrix):
        if matrix == None:
            
return rows = len(matrix) columns = len(matrix[0]) start = 0 while rows > start * 2 and columns > start * 2: self.PrintMatrixInCircle(matrix, columns, rows, start) start += 1 print('') def PrintMatrixInCircle(self, matrix, columns, rows, start): endX
= columns - 1 - start endY = rows - 1 - start # 從左到右列印一行 for i in range(start, endX+1): number = matrix[start][i] print("right",number, ' ', end='') # 從上到下列印一行 if start < endY: for i in range(start+1, endY+1): number
= matrix[i][endX] print("down",number, ' ', end='') # 從右到左列印一行 if start < endX and start < endY: for i in range(endX-1, start-1, -1): number = matrix[endY][i] print("left",number, ' ', end='') # 從下到上列印一行 if start < endX and start < endY-1: for i in range(endY-1, start, -1): number = matrix[i][start] print("up",number, ' ', end='') matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]] matrix2 = [[1],[2],[3],[4],[5]] matrix3 = [[1,2], [3,4], [5,6], [7,8], [9,10]] S = Solution() S.printMatrix(matrix) S.printMatrix(matrix2) S.printMatrix(matrix3)

outputs

macname@MacdeMBP ~ % python3 test.py
right 1  right 2  right 3  right 4  down 8  down 12  down 16  left 15  left 14  left 13  up 9  up 5  right 6  right 7  down 11  left 10  
right 1  down 2  down 3  down 4  down 5  
right 1  right 2  down 4  down 6  down 8  down 10  left 9  up 7  up 5  up 3  
macname@MacdeMBP ~ %