1. 程式人生 > 程式設計 >python實現資料結構中雙向迴圈連結串列操作的示例

python實現資料結構中雙向迴圈連結串列操作的示例

看此部落格之前建議先看看B站的視訊python資料結構與算法系列課程,該課程中未實現雙向迴圈連結串列的操作,所以我按照該視訊的連結串列思路實現了雙向迴圈連結串列的操作,歡迎大家閱讀與交流,如有侵權,請聯絡博主!

下面附上程式碼:

class Node:
  def __init__(self,elem):
    self.elem = elem
    self.prev = None
    self.next = None


class DoubleCycleLinkList:
  def __init__(self,node=None):
    self.__head = node

  def is_empty(self):
    """判空"""
    if self.__head is None:
      return True
    return False

  def length(self):
    """連結串列長度"""
    if self.is_empty():
      return 0
    cur = self.__head
    count = 1
    while cur.next is not self.__head:
      count += 1
      cur = cur.next
    return count

  def travel(self):
    """遍歷連結串列"""
    if self.is_empty():
      return
    cur = self.__head
    while cur.next is not self.__head:
      print(cur.elem,end=" ")
      cur = cur.next
    print(cur.elem,end=" ")
    print("")

  def add(self,elem):
    """頭插法"""
    node = Node(elem)
    if self.is_empty():
      self.__head = node
      node.prev = node
      node.next = node
    else:
      self.__head.prev.next = node
      node.prev = self.__head.prev
      node.next = self.__head
      self.__head.prev = node
      self.__head = node

  def append(self,elem):
    """尾插法"""
    node = Node(elem)
    if self.is_empty():
      self.__head = node
      node.prev = node
      node.next = node
    else:
      node.next = self.__head
      node.prev = self.__head.prev
      self.__head.prev.next = node
      self.__head.prev = node

  def insert(self,pos,elem):
    """任一位置(pos)插入, 下標從0數起"""
    if pos <= 0:
      self.add(elem)
    elif pos > (self.length() - 1):
      self.append(elem)
    else:
      count = 0
      cur = self.__head
      node = Node(elem)
      while count < (pos - 1):
        count += 1
        cur = cur.next
      node.next = cur.next
      node.prev = cur
      node.next.prev = node
      cur.next = node

  def remove(self,elem):
    """刪除某一節點,若有多個符合條件的節點,刪除第一個即可"""
    if self.is_empty():
      return
    cur = self.__head
    while cur.next is not self.__head:
      if cur.elem == elem:
        if cur is self.__head:
          self.__head = cur.next
          cur.prev.next = cur.next
          cur.next.prev = cur.prev
        else:
          cur.prev.next = cur.next
          cur.next.prev = cur.prev
        break
      cur = cur.next
    if cur.elem == elem:
      cur.prev.next = self.__head
      self.head = cur.prev

  def search(self,elem):
    """查詢某一個節點"""
    if self.is_empty():
      return False
    cur = self.__head
    while cur.next is not self.__head:
      if cur.elem == elem:
        return True
      cur = cur.next
    # while中處理不到尾節點,所以進行最後尾節點的判斷
    if cur.elem == elem:
      return True
    return False

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