python/golang實現迴圈連結串列的示例程式碼
阿新 • • 發佈:2020-09-15
迴圈連結串列就是將單鏈表的末尾指向其頭部,形成一個環。迴圈連結串列的增刪操作和單鏈表的增刪操作
區別不大。只是增加時,需要考慮空連結串列增加第一個節點的特殊情況;刪除時需考慮刪除節點是頭/尾節點,和連結串列中只有一個節點的特殊情況。
golang實現:
type Node struct { value int next *Node } type Circle struct { tail *Node lenth int } // 增加節點: func (c *Circle) add(value int) { newNode := &Node{value,nil} if c.lenth == 0 { //空連結串列中新增節點 c.tail = newNode c.tail.next = newNode } else { newNode.next = c.tail.next c.tail.next = newNode c.tail = newNode } c.lenth += 1 c.printCircle() } // 刪除節點: func (c *Circle) remove(v int) { if c.lenth == 0 { fmt.Println("空環") return } else if c.lenth == 1 && c.tail.value == v { //連結串列中只有一個節點的特殊情況 c.tail = nil c.lenth = 0 c.printCircle() return } pre := c.tail cur := c.tail.next // 頭節點 for i := 0; i < c.lenth; i++ { if cur.value == v { if cur == c.tail { //如果刪除的節點是尾節點,需更新tail c.tail = pre } pre.next = cur.next c.lenth -= 1 c.printCircle() return } pre = cur cur = cur.next } fmt.Println(v,"不在環中") } //列印節點: func (c *Circle) printCircle() { if c.lenth == 0 { fmt.Println("空環") return } cur := c.tail.next // 頭節點 for i := 0; i < c.lenth; i++ { fmt.Printf("%d ",cur.value) cur = cur.next } fmt.Println() } func testCircle() { var circle *Circle = new(Circle) //for i := 1; i <=41; i++ { // circle.add(i) //} circle.add(1) circle.remove(10) circle.printCircle() }
python實現:
class Node: def __init__(self,value,next=None): self.value = value self.next = next def __str__(self): return str(self.value) class Circle: def __init__(self): self.tail = None self.lenth = 0 # 增加節點 def add(self,v): new_node = Node(v) if self.lenth == 0: # 空連結串列中新增節點 self.tail = new_node self.tail.next = new_node else: new_node.next = self.tail.next self.tail.next = new_node self.tail = new_node self.lenth += 1 # 刪除節點 def remove(self,v): if self.lenth == 0: print("空環") return elif self.lenth == 1 and self.tail.value == v: # 連結串列中只有一個節點的特殊情況 self.tail = None self.lenth = 0 return pre = self.tail cur = self.tail.next # 頭節點 for i in range(self.lenth): if cur.value == v: if cur == self.tail: # 如果刪除的節點是尾節點,需更新tail self.tail = pre pre.next = cur.next self.lenth -= 1 return pre = cur cur = cur.next print(v,"不在環中") # 列印連結串列 def print_circle(self): if self.lenth == 0: print('空環') return cur = self.tail.next # 頭節點 for i in range(self.lenth): print(cur,end=" ") cur = cur.next print() def test(): c = Circle() for i in range(10): c.add(i) c.print_circle() c.remove(0) c.print_circle() c.remove(10) c.print_circle() c.remove(9) c.print_circle() c.remove(4) c.print_circle()
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