【python-redis實現簡單的佇列pub/sub】
阿新 • • 發佈:2020-10-20
需求:本次專案需求是自己用flask設計一個api,接受一些引數,然後使用佇列動態將引數傳給後臺的worker,在此總結一下redis的pub# -*- coding: utf-8 -*-from flask import Flask
from flask import request, jsonify from redis import Redis app = Flask(__name__) @app.route("/v1/enc-aab", methods=["POST"]) def first_post(): """函式主體""" data = request.get_json() path= data.get('path') name = data.get('name') res = {'path': path, 'name': name} print(res) # 業務處理 if not all([path, name]): return jsonify(msg='引數不完整') else: # 資料完整 開始pub rc = Redis(host='127.0.0.1', port=6379, db=0) rc.pubsub() rc.publish('res', res)
return jsonify(status='ok') if __name__ == '__main__': app.run()
到此為止就在介面中拿到了傳遞的data並pub進了queue
pub的總結如下:
# ##### rc = Redis(host='127.0.0.1', port=6379, db=0) rc.pubsub() rc.publish('res', res) # #####
sub的應用如下:
# ###### rc = Redis(host='127.0.0.1', port=6379, db=0) ps= rc.pubsub() ps.subscribe(['res']) for item in ps.listen(): print(item) # ######