HDU 1040 As Easy As A+B
阿新 • • 發佈:2020-10-21
HDU 1040 As Easy As A+B
題意:T組資料
一組先給個N
後面給N個數
將這N個數從小到大排列
解題思路:
究極水題,直接sort解決
程式碼如下:
1 #include <bits/stdc++.h> 2 #define mem(a) memset(a,0,sizeof(a)) 3 #define mem1(a) memset(a,-1,sizeof(a)) 4 #define forn(i,n) for(int i=0;i<n;++i) 5 #define for1(i,n) for(int i=1;i<=n;++i) 6 #define IO std::ios::sync_with_stdio(false); std::cin.tie(0) 7#define ll long long 8 #define LL long long 9 #define inf 0x3f3f3f3f 10 #define INF 0x3f3f3f3f3f3f3f3f 11 #define N 1000000 12 using namespace std; 13 const int maxn=1e3+50; 14 //ll gcd(ll a, ll b){return b ? gcd(b, a % b) : a;} 15 //ll lcm(ll a, ll b){return a * b / gcd(a, b);} 16 17 int num[maxn]; 18 19 intmain() 20 { 21 int T,n,m; 22 scanf("%d",&T); 23 while(T--) 24 { 25 ll tmp,ans=1; 26 scanf("%d",&n); 27 forn(i,n) 28 { 29 scanf("%lld",&num[i]); 30 } 31 sort(num,num+n); 32 for(int i=0;i<n;++i) 33 {34 if(i==0) 35 printf("%d",num[i]); 36 else 37 printf(" %d",num[i]); 38 } 39 printf("\n"); 40 } 41 return 0; 42 }