1. 程式人生 > 實用技巧 >Codeforces Round #677 (Div. 3)【ABCDE】

Codeforces Round #677 (Div. 3)【ABCDE】

思路

這裡使用層序遍歷產生的序列當成序列化,再使用此序列層序建立二叉樹即對應反序列化。

使用“#”代表空節點,並且各節點的值在序列化的字串中以空格分隔。

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Codec { 11 public: 12 13 // Encodes a tree to a single string. 14 //層序遍歷二叉樹, #代表空節點 15 string serialize(TreeNode* root) { 16 if(root == NULL) 17 return ""; 18 19 string res = ""; 20 queue<TreeNode*> Q; 21 Q.push(root); 22 while
(!Q.empty()) { 23 TreeNode *t = Q.front(); 24 Q.pop(); 25 26 if(t != NULL) { 27 res += to_string(t->val) + " "; 28 Q.push(t->left); 29 Q.push(t->right); 30 } else { 31 res += "
# "; 32 } 33 } 34 return res; 35 } 36 37 // Decodes your encoded data to tree. 38 //層序建立二叉樹 39 TreeNode* deserialize(string data) { 40 if(data == "") 41 return NULL; 42 43 istringstream is(data); 44 string value; 45 is >> value; 46 TreeNode *node = new TreeNode(stoi(value)); 47 queue<TreeNode*> Q; 48 Q.push(node); 49 while(!Q.empty()) { 50 TreeNode *t = Q.front(); 51 Q.pop(); 52 53 string lvalue, rvalue; 54 is >> lvalue; 55 is >> rvalue; 56 57 if(lvalue == "#") { 58 t->left = NULL; 59 } else { 60 t->left = new TreeNode(stoi(lvalue)); 61 Q.push(t->left); 62 } 63 64 if(rvalue == "#") { 65 t->right = NULL; 66 } else { 67 t->right = new TreeNode(stoi(rvalue)); 68 Q.push(t->right); 69 } 70 } 71 72 return node; 73 } 74 }; 75 76 // Your Codec object will be instantiated and called as such: 77 // Codec codec; 78 // codec.deserialize(codec.serialize(root));