java 紅包案例 小白 不是最好方案 新增成員需要new 還得調收紅包的方法 不調不會收

//父類 群類
public class Group {
    private String name;//名字
    private String position;//職位
    private double balance;//餘額
    static int memberNum;//人數

    //構造方法
    public Group() {
    }

    public Group(String name, String position, double balance) {
        this.name = name;
        this.position = position;
        this.balance = balance;
    }

    //getXxx() setXxx()
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getPosition() {
        return position;
    }

    public void setPosition(String position) {
        this.position = position;
    }

    public double getBalance() {
        return balance;
    }

    public void setBalance(double balance) {
        this.balance = balance;
    }

}





 

//群主類 繼承群類

import java.util.ArrayList;
import java.util.Random;

public class GroupOwner extends Group {
    static ArrayList<Double> arrPart = new ArrayList<>();//把發出來的隨機紅包金額 賦給arrPart陣列

    //構造方法
    public GroupOwner() {
    }

    public GroupOwner(String name, String position, double balance) {
        this.setName(name);
        this.setPosition(position);
        this.setBalance(balance);
    }

    //發紅包方法  引數有錢和要發幾份
    public void giveRedEnvelopes(double money, int numPeople) {
        //發的錢從群主餘額扣除
        setBalance(getBalance() - money);
        //初始化
        arrPart = new ArrayList<>();
        double aceilingName = 0;//不能超出傳來的money總數
        for (int i = 0; i < numPeople; i++) {//用份數當迴圈條件  可以人少份數多

            Random random = new Random();

            //隨機多少錢 隨機條件是 發的錢數/份數*2 公平點（隨機）
            double nextInt = random.nextDouble() * (money / numPeople*2);

            if (aceilingName >= money) {//發的份數的總錢數大於總錢數 退出
                break;
            } else if (i == numPeople - 1) {//最後一份 把剩下的全拿走
                arrPart.add(money - aceilingName);

            } else {//其他隨機
                arrPart.add(nextInt);
            }
            aceilingName += nextInt;//疊加 發出去的份數 和錢數
        }

        System.out.println(getName() + "群主發了：" + money);

        for (int i = 0; i < arrPart.size(); i++) {//遍歷 隨機紅包金額的錢 陣列 展示紅包
            if (i == arrPart.size()) {//防止越界
                System.out.println("第" + i + "個紅包為：" + arrPart.get(i));
                break;
            } else {
                System.out.println("第" + (i + 1) + "個紅包為：" + arrPart.get(i));//索引對應紅包數，索引從0開始所以要+1
            }

        }
    }
}





 

//成員類

import java.util.ArrayList;
import java.util.Random;

public class Member extends Group {
    static ArrayList<Double> max = new ArrayList<>();//這個陣列用來儲存接收的紅包錢數判斷誰是手氣王
    static ArrayList<String> name = new ArrayList<>();//這個陣列用來儲存名字的

    //構造方法
    public Member() {
    }

    public Member(String name, String position, double balance) {
        Group.memberNum++;//調一次全參構造群人數就加一
 

        this.setName(name);
        this.setPosition(position);
        this.setBalance(balance);
    }

    //收紅包方法
    public void receiveLuckyMoney() {

        double remove = 0;
        //遍歷 群主發的紅包陣列
        for (int i = 0; i < GroupOwner.arrPart.size(); i++) {
            //隨即索引 取出 對應的紅包
            int nextInt = new Random().nextInt(GroupOwner.arrPart.size());
            //取出 刪除 返回值為：獲取的錢數
            remove = GroupOwner.arrPart.remove(nextInt);

            //調一次就把獲得的餘額 和姓名 傳給對應的陣列
            max.add(remove);
            name.add(getName());

            //領取後把錢加到自己的餘額中
            setBalance(getBalance() + remove);
            System.out.println(getName() + "領取了：" + remove + "元" + "。現在餘額為：" + getBalance() + "元");
            break;

        }
    }
}

//測試 群 類
import java.util.Scanner;

public class TestGroup {
    public static void main(String[] args) {
        //構造群主
        GroupOwner groupOwner = new GroupOwner("張三", "群主", 5000);


        //構造成員

        Member member01 = new Member("李四", "成員", 500);
        Member member02 = new Member("王五", "成員", 700);
        Member member03 = new Member("趙六", "成員", 888);
        Member member04 = new Member("田七", "成員", 999);

        System.out.println("群里人數為：" + Group.memberNum);

        //發多少錢紅包和個數
        Scanner scanner = new Scanner(System.in);
        System.out.println("輸入發多少錢：");
        double money = scanner.nextDouble();
        System.out.println("發幾份：");
        int peopleNum = scanner.nextInt();
        groupOwner.giveRedEnvelopes(money, peopleNum);

        //收紅包
        member01.receiveLuckyMoney();
        member02.receiveLuckyMoney();
        member03.receiveLuckyMoney();
        member04.receiveLuckyMoney();

        //手氣王
        double temp = 0;//max 獲得的紅包錢數的中間變數
        String maxName;//name 名字要隨著紅包變化而變化 就可以實現一一對應
        //排序 降序 第一個索引就為最大值 名字和錢數一起變 所以就可以一一對應起來了
        for (int i = 0; i < Member.max.size(); i++) {
            for (int j = 0; j < Member.max.size() - 1; j++) {
                if (Member.max.get(j) < Member.max.get(j + 1)) {
                    temp = Member.max.get(j);
                    Member.max.set(j, Member.max.get(j + 1));
                    Member.max.set(j + 1, temp);

                    //隨著餘額索引變化 而變化
                    maxName = Member.name.get(j);
                    Member.name.set(j, Member.name.get(j + 1));
                    Member.name.set(j + 1, maxName);
                }
            }
        }
        System.out.println("手氣王為：" + Member.name.get(0) + "  抽取了：" + Member.max.get(0) + "元");
    }
}