20192320楊坤資料結構實驗八
阿新 • • 發佈:2020-12-09
《資料結構與面向物件程式設計》實驗八報告
課程:《程式設計與資料結構》
班級: 1923
姓名: 楊坤
學號:20192320
實驗教師:王自強
實驗日期:2020年12月3日
必修/選修: 必修
1.實驗內容
參考教材PP16.1,完成鏈樹LinkedBinaryTree的實現(getRight,contains,toString,preorder,postorder)
用JUnit或自己編寫驅動類對自己實現的LinkedBinaryTree進行測試,提交測試程式碼執行截圖,要全屏,包含自己的學號資訊
課下把程式碼推送到程式碼託管平臺
基於LinkedBinaryTree,實現基於(中序,先序)序列構造唯一一棵二㕚樹的功能,比如給出中序HDIBEMJNAFCKGL和後序ABDHIEJMNCFGKL,構造出附圖中的樹
用JUnit或自己編寫驅動類對自己實現的功能進行測試,提交測試程式碼執行截圖,要全屏,包含自己的學號資訊
課下把程式碼推送到程式碼託管平臺
自己設計並實現一顆決策樹
提交測試程式碼執行截圖,要全屏,包含自己的學號資訊
課下把程式碼推送到程式碼託管平臺
輸入中綴表示式,使用樹將中綴表示式轉換為字尾表示式,並輸出字尾表示式和計算結果(如果沒有用樹,正常評分。如果用到了樹,即使有小的問題,也酌情給滿分)
提交測試程式碼執行截圖,要全屏,包含自己的學號資訊
程式碼
public interface BinaryTreeADT<T> { public T getRootElement(); public boolean isEmpty(); public int size(); public int height(); public boolean contains(T target); public BinaryTreeNode find(T target); public String IteratorInorder(); public String IteratorPreorder(); public String IteratorPostorder(); public String IteratorLevel(); }
public class BinaryTreeNode<T> { protected T element; protected BinaryTreeNode left, right; public BinaryTreeNode() { element = null; left = null; right = null; } public BinaryTreeNode(T element) { this.element = element; left = right = null; } public BinaryTreeNode getLeft() { return left; } public BinaryTreeNode getRight() { return right; } public void setLeft(BinaryTreeNode left) { this.left = left; } public void setRight(BinaryTreeNode right) { this.right = right; } public BinaryTreeNode find(T target) { BinaryTreeNode result = null; if (element.equals(target)) return this; else { if (left != null) result = left.find(target); if (right != null) result = right.find(target); } return result; } public int count() { int counter = 1; if (left != null) counter += left.count(); if (right != null) counter += right.count(); return counter; } public int level() { int level = 1, max = 0; if (left != null) { max = left.level(); } if (right != null && right.level() > max) max = right.level(); return level + max; } public String IteratorInOrder() { String s = ""; if (left != null) s += left.IteratorInOrder(); s += this.element.toString() + " "; if (right != null) s += right.IteratorInOrder(); return s; } public String IteratorPreOrder() { String s = ""; s += this.element.toString() + " "; if (left != null) s += left.IteratorPreOrder(); if (right != null) s += right.IteratorPreOrder(); return s; } public String IteratorPostOrder() { String s = ""; if (left != null) s += left.IteratorPostOrder(); if (right != null) s += right.IteratorPostOrder(); s += this.element.toString() + " "; return s; } public BinaryTreeNode Insert(char s) { BinaryTreeNode result = null; if (left == null) { left = new BinaryTreeNode(s); result=left; } else if(!left.element.equals('#'))result=left.Insert(s); if(result==null){ if (right == null) { right= new BinaryTreeNode(s); result=right; } else if(!right.element.equals('#'))result=right.Insert(s); } return result; } public void Insert1(String a,String b) { int i = 0, j; for (j = 0; b.charAt(j) != a.charAt(i) && j < b.length(); j++) ; if (left == null) { if(j!=0) { left = new BinaryTreeNode(a.charAt(1)); left.Insert1(a.substring(i + 1, j + 1), b.substring(0, j)); } } if (right == null) { if(j!=b.length()-1) { right = new BinaryTreeNode(a.charAt(j + 1)); right.Insert1(a.substring(j + 1), b.substring(j + 1)); } } } }
public class LinkedBinaryTree <T>implements BinaryTreeADT{
BinaryTreeNode root;
public LinkedBinaryTree(){
root=null;
}
public LinkedBinaryTree(T element){
root=new BinaryTreeNode(element);
}
public LinkedBinaryTree(T element,LinkedBinaryTree left,LinkedBinaryTree right){
root=new BinaryTreeNode(element);
root.setLeft(left.root);
root.setRight(right.root);
}
@Override
public T getRootElement() {
if(root==null)return null;
return (T) root.element;
}
@Override
public boolean isEmpty() {
if(root==null)return true;
else return false;
}
public LinkedBinaryTree getLeft(){
if(root==null)return null;
LinkedBinaryTree result = new LinkedBinaryTree();
result.root = root.getLeft();
return result;
}
public LinkedBinaryTree getRight(){
if(root==null)return null;
LinkedBinaryTree result = new LinkedBinaryTree();
result.root = root.getRight();
return result;
}
public void CreateTree(String s){
root=new BinaryTreeNode(s.charAt(0));
for(int i=1;i<s.length();i++){
root.Insert(s.charAt(i));
}
}
public void CreateTree1(String a,String b){
root=new BinaryTreeNode(a.charAt(0));
root.Insert1(a,b);
}
@Override
public int size() {
if(root==null)return 0;
return root.count();
}
@Override
public int height() {
if(root==null)return 0;
return root.level();
}
@Override
public boolean contains(Object target) {
if(root==null)return false;
T a=(T)target;
if(root.find(a)==null)return false;
else return true;
}
@Override
public BinaryTreeNode find(Object target) {
if(root==null)return null;
T a=(T)target;
return root.find(a);
}
@Override
public String IteratorInorder() {
if(root==null)return null;
else return root.IteratorInOrder();
}
@Override
public String IteratorPreorder() {
if(root==null)return null;
else return root.IteratorPreOrder();
}
@Override
public String IteratorPostorder() {
if(root==null)return null;
else return root.IteratorPostOrder();
}
@Override
public String IteratorLevel() {
String s="";
int i,j,count=1;
int t[]=new int[20];
BinaryTreeNode m[]=new BinaryTreeNode [20];
m[0]=root;
t[0]=count;
for(i=0,j=1,count=2;i!=j;i++){
if(m[i].left!=null){m[j]=m[i].left;t[j]=t[i]+1;j++;}
if(m[i].right!=null){m[j]=m[i].right;t[j]=t[i]+1;j++;}
s+=m[i].element+" ";
if(t[i+1]!=t[i]) s+="\n";
}
return s;
}
public String ToString(){
return root.IteratorPreOrder();
}
}
public class BStest {
public static void main(String[] args) {
LinkedBinaryTree tree=new LinkedBinaryTree();
tree.CreateTree1("ABDHIEJMNCFGKL","HDIBEMJNAFCKGL");
System.out.println(tree.IteratorLevel());
}
}
public class decisionTree<T> {
public static void main(String[] args) {
String e0 = "開始遊戲!選擇亞索還是勁夫?";
String e1 = "你這把選擇亞索";
String E1 = "你這把選擇勁夫";
String m1 = "這把亞索你選擇什麼天賦呢?";
String e2 = "這把你亞索選擇天賦:迅捷步伐";
String E2 = "這把你亞索選擇天賦:征服者";
String e3 = "這把你勁夫選擇天賦:叢刃";
String E3 = "這把你勁夫選擇天賦:征服者";
String e4 = "你這把選擇走上路";
String E4 = "你這把選擇走中路";
String e5 = "這把遊戲輸了,亞索是孤兒";
String e6 = "這把遊戲輸了,但是你快樂到了太空";
String e7 = "這把遊戲輸了,沒有女性角色,勁夫不好發揮";
String e8 = "這把遊戲贏了,萬豪帶叢刃,勁夫變葉問";
String E7 = "輸了,勁夫倒了(哭腔)";
String E8 = "勁夫勁夫,全場蕪湖";
String choose = "0";
BTNode<String> n1, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, n12, n13, n14, n15, N2;
TreeNode treeNode = new TreeNode();
treeNode.insert(e0);
/*System.out.println(e1);
treeNode.insert('Y');
treeNode.insert('N');
System.out.println(e2);
treeNode.insert('Y');
treeNode.insert('N');*/
//選擇英雄
n1 = treeNode.otherInsert(treeNode.root, e1, E1);
//選擇天賦
n2 = treeNode.otherInsert(n1.left, e2, E2);
n3 = treeNode.otherInsert(n1.right, e3, E3);
//選擇對線路
n4 = treeNode.otherInsert(n2.left, e4, E4);
n5 = treeNode.otherInsert(n2.right, e4, E4);
n6 = treeNode.otherInsert(n3.left, e4, E4);
n7 = treeNode.otherInsert(n3.right, e4, E4);
//遊戲結果
n8 = treeNode.otherInsert(n4.left, e5, e5);
n9 = treeNode.otherInsert(n4.right, e6, e6);
n10 = treeNode.otherInsert(n5.left, e5, e5);
n11 = treeNode.otherInsert(n5.right, e5, e5);
n12 = treeNode.otherInsert(n6.left, e7, e7);
n13 = treeNode.otherInsert(n6.right, e8, e8);
n14 = treeNode.otherInsert(n7.left, E8, E8);
n15 = treeNode.otherInsert(n7.right, E7, E7);
BTNode current = new BTNode();
Scanner scanner = new Scanner(System.in);
current = treeNode.root;
System.out.println("選擇英雄"+"\n"+"選擇天賦:"+"\n"+"亞索:迅捷步伐與征服者 "+" 勁夫:叢刃與征服者"+"\n"+"選擇上路還是中路");
while (treeNode.size(current) >2 ) {
System.out.println(current.data);
System.out.println("選擇第一個輸入Y第二個輸入N");
if (scanner.nextLine().equalsIgnoreCase("N"))
current = current.right;
else current = current.left;
}
current=current.left;
System.out.println(current.data);
}
}
中綴的程式碼:
public class MiddleToRear {
public static void main(String[] args) {
//不用索引掃描表示式,將表示式加入到list中
String expression;
Scanner scanner=new Scanner(System.in);
expression=scanner.next();
//得到中綴表示式轉為list的集合
List<String> list=getList(expression);
//將中綴表示式的集合轉到字尾表示式的集合
List<String> rearList=getRearList(list);
System.out.println("rearList = " + rearList);
//輸出計算結果
System.out.println(getResult(rearList));
}
//中綴表示式的集合轉為字尾表示式的集合
private static List<String> getRearList(List<String> list) {
ArrayList<String> rearList = new ArrayList<>();
//定義符號棧
Stack<String> operatorStack = new Stack<>();
//定義集合代替數字棧,數字棧本身並沒有pop操作,並且最後要倒敘輸出,隨意用list代替
ArrayList<String> numList = new ArrayList<>();
for (String s : list) {
//如果是個數字
if (s.matches("\\d+")){
numList.add(s);
}else if (s.equals("(")){
operatorStack.push(s);
}else if (s.equals(")")){
//符號棧棧頂直到左括號之前的符號放入數字棧
while (!"(".equals(operatorStack.peek())){
numList.add(operatorStack.pop());
}
//把左括號彈出來
operatorStack.pop();
//判斷優先順序,當前符號優先順序小於等於符號棧棧頂優先順序,將符號棧棧頂彈出加入數字棧,
//直到找到當前符號優先順序大於符號棧棧頂優先順序為止,再將當前符號加入符號棧
}else{
while (operatorStack.size()!=0 && (OperPriority.getPriority(s) <= OperPriority.getPriority(operatorStack.peek()))){
numList.add(operatorStack.pop());
}
//將當前符號加入符號棧
operatorStack.push(s);
}
}
//將符號棧中剩餘符號加入數字棧
while (operatorStack.size()!=0){
numList.add(operatorStack.pop());
}
return numList;
}
//將中綴表示式的各個字元存到list集合,方面遍歷
private static List<String> getList(String expression) {
ArrayList<String> list = new ArrayList<>();
int index=0;
String str=""; //多位數的拼接
char c; //用於存放每次掃描到的結果
do {
//判斷是否為數字,非數字直接加入list
c=expression.charAt(index);
if (c < 48 || c >57){
list.add(""+c);
}else {//數字.考慮可能不是一位數,字串拼接
str+=c;
if (index == expression.length()-1){
list.add(str);
}else {
if (expression.charAt(index+1) < 48 || expression.charAt(index+1) > 57){
list.add(str);
str="";
}
}
}
index++;
}while (index < expression.length());
return list;
}
//輸出計算結果
private static int getResult(List<String> list) {
Stack<String> stack = new Stack<>();
for (String s : list) {
//匹配數字
if (s.matches("\\d+")){
stack.push(s);
}else {
int num01=Integer.parseInt(stack.pop());
int num02=Integer.parseInt(stack.pop());
int result=0;
if (s.equals("+")){
result=num01+num02;
}else if (s.equals("-")){
result=num02-num01;
}else if (s.equals("*")){
result=num02*num01;
}else if (s.equals("/")){
result=num02/num01;
}else {
throw new RuntimeException("無法解析的字串");
}
stack.push(""+result);
}
}
return Integer.parseInt(stack.pop());
}
}
截圖:
2.實驗心得體會
自身的自學能力還要提升,大多數的實驗程式碼都在同學的幫助下完成,在運到困難時,容易感到沮喪,還要多鍛鍊自己。平時也要多加練習。
這是一個新的軟體,一切都是陌生的,在遇到這種問題的時候,多上網蒐集資料是非常必要的,同時多家運用學習的app在上面觀看相關的視訊能夠更好的掌握。