使用Linq的Intersect與Except方法的例項
阿新 • • 發佈:2020-12-17
例項描述:
現有某班學生的兩份成績,兩份成績中存在一些不一致的記錄。需藉助於程式設計方法找出這些不一致的記錄
例項程式碼:
using System; using System.Collections.Generic; using System.Linq; namespace IntersectAndExceptExp { class Program { static void Main(string[] args) { List<Student> studentList1 = newList<Student>() {new Student(){StudentId=1,Score=64}, new Student(){StudentId=2,Score=85}, new Student(){StudentId=3,Score=78}, new Student(){StudentId=4,Score=94}, new Student(){StudentId=5,Score=90} }; List<Student> studentList2 = newList<Student>() {new Student(){StudentId=1,Score=64}, new Student(){StudentId=2,Score=80}, new Student(){StudentId=3,Score=78}, new Student(){StudentId=4,Score=94}, new Student(){StudentId=5,Score=95} }; var both = studentList1.Intersect(studentList2,newStudentComparer()); var diff1 =studentList1.Except(both, new StudentComparer()); var diff2 =studentList2.Except(both, new StudentComparer()); Console.WriteLine("-------------下面是兩份成績中不同的記錄--------------"); Console.WriteLine("-------------第一份學生成績--------------"); foreach (var s in diff1) { Console.WriteLine("StudentId:"+s.StudentId+";Score:"+s.Score); } Console.WriteLine("-------------第一份學生成績--------------"); foreach (var s in diff2) { Console.WriteLine("StudentId:"+ s.StudentId + ";Score:" + s.Score); } } } public class Student { public int StudentId { get; set; } public int Score { get; set; } } public class StudentComparer : IEqualityComparer<Student> { public bool Equals(Student x, Studenty) { if (Object.ReferenceEquals(x, y)) returntrue; return x != null && y != null&& x.StudentId == y.StudentId && x.Score == y.Score; } public int GetHashCode(Student obj) { int hashStudentId =obj.StudentId.GetHashCode(); int hashScore =obj.Score.GetHashCode(); return hashStudentId ^ hashScore; } } }
程式碼說明:
先使用Intersect方法生成兩份記錄的交集,該方法會使用傳入的比較器對值進行比較決定記錄是否相同。基於前步生成的交集,再使用Except方法找出兩份記錄中不一致的記錄,該方法同樣使用傳入的比較器對值進行比較決定記錄是否相同。