sizeof(a)/sizeof(a[0])

#include<stdio.h>
int main()
{
	int a[5]={1,2,3,4,5};
	int b[10]={1,2,3,4,5,6,7,8,9,0};
	double c[5]={1.1,2.2,3.3,4.4,5.5};
	double n;
	
	n=sizeof(c)/sizeof(c[0]);
	
	printf("len(a)=%d\n",sizeof(a)/sizeof(a[0]));
	printf
 
("len(b)=%d\n",sizeof(b)/sizeof(b[0]));
	printf("len(c)=%lf\n",n);
	
	return 0;
}

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