1. 程式人生 > 實用技巧 >學習記錄--C++多型性簡答+程式設計題

學習記錄--C++多型性簡答+程式設計題

#include<iostream>
#include<string>
//雙目運算子:運算子作用域兩個運算元
//定義一個複數類,過載“+”,作為複數類的成員函式,使這個運算子能直接完成兩個複數的加法運算,以及一個複數與一個實數的加法運算
using namespace std;
class Complex
{
public:
    Complex(int r = 0, int i = 0)
    {
        m_r = r;
        m_i = i;
    }
    Complex operator+(Complex  complex);
    void
Print(); ~Complex(){} private: int m_r; int m_i; }; Complex Complex::operator+(Complex complex) { Complex t; t.m_r = m_r + complex.m_r; t.m_i = m_i + complex.m_i; return t; } void Complex::Print() { if (m_i < 0) { cout << m_r << m_i << "
i" << endl; } else cout << m_r << "+" << m_i << "i" << endl; } int main() { Complex c1(10, 13), c2(9, 2), c3; c1.Print(); c2.Print(); c3 = c1 + c2; c3.Print(); system("pause"); return 0; }

程式設計題

封裝一個CStudent類,用來描述學生的屬性和行為。具體要求如下。

1.學生有姓名,籍貫,學號,年齡,成績五個成員資料,編寫建構函式,拷貝建構函式,同時編寫Display(),成員函式顯示學生的資訊。
2.編寫“+”運算子過載函式,使CStudent類的兩個物件相加返回兩個物件總成績相加的和。
3.編寫主函式,定義兩個CStudent類物件,分別呼叫成員函式Display(),顯示兩個物件的學生資訊,同時顯示兩個物件相加的結果

#include<iostream>
#include<string>
using namespace std;
class Cstudent
{
public:
    Cstudent(string name="", string jiguan="", int id=0, int age=0, int score=0)
    {
        m_name = name;
        m_jiguan = jiguan;
        m_ID = id;
        m_Age = age;
        m_Score = score;
    }
    //拷貝建構函式
    Cstudent(const Cstudent& p)
    {
        m_name = p.m_name;
        m_jiguan = p.m_jiguan;
        m_ID = p.m_ID;
        m_Age = p.m_Age;
        m_Score = p.m_Score;
    }
    int getScore()
    {
        return m_Score;
    }
    void Display()
    {
        cout << "姓名:" << m_name << "\t" << "籍貫:" << m_jiguan << "\t" << "學號:" << m_ID << "\t" << "年齡:" << m_Age << "\t" << "成績:" << m_Score << endl;
    }
    Cstudent operator+(Cstudent student);
private:
    string m_name;
    string m_jiguan;
    int m_ID;
    int m_Age;
    int m_Score;
};

Cstudent Cstudent::operator+(Cstudent  student)
{
    Cstudent s1;
    s1.m_Score = m_Score + student.m_Score;
    return s1;
}

int main()
{
    Cstudent c1("JIN", "果川",1, 18, 98);
    Cstudent c2("SUGA", "大邱", 2, 17, 100);
    Cstudent c3;
    c1.Display();
    c2.Display();
    c3 = c1 + c2;
    cout << "成績總和為:" <<c3.getScore()<< endl;
    system("pause");
    return 0;
}

2.設計一個三角形類Triangle,包含三角形三條邊長的私有資料成員,另有一個過載運算子”+”,以實現求兩個三角形物件的面積之和

#include<iostream>
#include<algorithm>
#include<string>
#include<cmath>
using namespace std;
class Triangle
{
public:
    Triangle(double s1 = 0, double s2 = 0, double s3 = 0, double area=0)
    {
        m_s1 = s1;
        m_s2 = s2;
        m_s3 = s3;
        m_area = area;
    }
    double getS1()
    {
        return m_s1;
    }
    double getS2()
    {
        return m_s2;
    }
    double getS3()
    {
        return m_s3;
    }
    double getArea()
    {
        return m_area;
    }
    Triangle operator+(Triangle triangle);
private:
    double m_s1;
    double m_s2;
    double m_s3;
    double m_area;
};
Triangle Triangle::operator+(Triangle triangle)
{
    Triangle t1;
    double p = (m_s1 + m_s2 + m_s3)/2;
    double p1 = (triangle.m_s1 + triangle.m_s2 + triangle.m_s3)/2;
    double d= p*(p - m_s1) * (p - m_s2) * (p - m_s3);
    double d1 = p1 * (p1 - triangle.m_s1) * (p1 - triangle.m_s2) * (p1 - triangle.m_s3);
    double area = sqrt(d);
    double area1 = sqrt(d1);
    t1.m_area = area + area1;
    return t1;
}
int main()
{
    Triangle c1(3,4,5), c2(6,8,10),c3;
    c3 = c1 + c2;
    cout << "兩個三角形面積之和為:" << c3.getArea() << endl;
    system("pause");
    return 0;
}