技術標籤：Codeup新家

#include<cstdio>
#include<cstring>
int main(){
	char a[20], b[20];
	int sum = 0;
	int i = 0;
	int j = 0;
	int temp = 0;
	while(scanf("%s %s", a, b) != EOF){
		for(i = 0; i < strlen(a); i++){
			for(j = 0; j < strlen(b); j++){
				temp = (a[i]-'0') * (b[j]-'0');
				sum +
 
= temp;
			}
		}
		printf("%d\n", sum);
		sum = 0;
	}
	
	return 0;
}

麻煩寫法

#include<cstdio>
#include<cstring>
void split(char *str, int *ileft, int *iright);
void transition(char *str, int *num);
int getResult(char *str);
int main(){
	char str[1000];
	while(gets(str) != NULL){
		printf
 
("%d\n", getResult(str));
	}
	return 0;
}
void split(char *str, int *ileft, int *iright){
	char cleft[1000], cright[1000];
	sscanf(str, "%s %s", cleft, cright);
	transition(cleft, ileft);
	transition(cright, iright);
}
void transition(char *str, int *num){
	int len = strlen(str);
	int tempnum =
 
 0;
	int temp = 0;
	sscanf(str, "%d", &tempnum);
	int i = 0;
	num[0] = len;
	for(i = 1; i <= len; i++){
		temp = tempnum % 10;
		num[i] = temp;
		tempnum /= 10;
	}
}
int getResult(char *str){
	int left[1000] = {0};
	int right[1000] = {0};
	split(str, left, right);
	int i = 0;
	int j = 0;
	int sum = 0;
	for(i = 1; i <= left[0]; i++){
		for(j = 1; j <= right[0]; j++){
			sum += left[i] * right[j];
		}
	}
	return sum; 
}