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【LabVIEW】如何通過程式改變LabVIEW中輸入控制元件或顯示控制元件的標籤

You are given anm x nbinary matrixgrid. An island is a group of1's (representing land) connected4-directionally(horizontal or vertical.) You may assume all four edges of the grid are surrounded by water.

Theareaof an island is the number of cells with a value1in the island.

Returnthe maximumareaof an island in

grid. If there is no island, return0.

Example 1:

Input: grid = [[0,0,1,0,0,0,0,1,0,0,0,0,0],[0,0,0,0,0,0,0,1,1,1,0,0,0],[0,1,1,0,1,0,0,0,0,0,0,0,0],[0,1,0,0,1,1,0,0,1,0,1,0,0],[0,1,0,0,1,1,0,0,1,1,1,0,0],[0,0,0,0,0,0,0,0,0,0,1,0,0],[0,0,0,0,0,0,0,1,1,1,0,0,0],[0,0,0,0,0,0,0,1,1,0,0,0,0]]
Output: 6
Explanation: The answer is not 11, because the island must be connected 4-directionally.

Example 2:

Input: grid = [[0,0,0,0,0,0,0,0]]
Output: 0

Constraints:

  • m == grid.length
  • n == grid[i].length
  • 1 <= m, n <= 50
  • grid[i][j]is either0or1.
class Solution {
    public int maxAreaOfIsland(int[][] grid) {
        int res = 0;
        for(int i = 0; i < grid.length; i++) {
            for(int j = 0
; j < grid[0].length; j++) { if(grid[i][j] == 1) { res = Math.max(res, dfs(i, j, grid)); } } } return res; } public int dfs(int i, int j, int[][] grid) { if(i >= grid.length || i < 0 || j < 0 || j >= grid[0].length || grid[i][j] == 0) return 0; grid[i][j] = 0; return 1 + dfs(i, j - 1, grid)+ dfs(i-1, j, grid)+ dfs(i+1, j, grid)+ dfs(i, j+1, grid); } }

similar to #200.