leetcode-----40. 組合總和 II
阿新 • • 發佈:2020-07-06
程式碼(dfs)
class Solution { public: vector<vector<int>> ans; vector<int> path; vector<vector<int>> combinationSum2(vector<int>& candidates, int target) { sort(candidates.begin(), candidates.end()); dfs(candidates, 0, target); return ans; } void dfs(vector<int> &cs, int u, int target) { if (target == 0) { ans.push_back(path); return; } if (u == cs.size()) return; int k = u + 1; while (k < cs.size() && cs[k] == cs[u]) k++; int cnt = k - u; for (int i = 0; cs[u] * i <= target && i <= cnt; ++i) { dfs(cs, k, target - cs[u] * i); path.push_back(cs[u]); } for (int i = 0; cs[u] * i <= target && i <= cnt; ++i) { path.pop_back(); } } };