Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification

Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).

Output Specification

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input

12345

Sample Output

one five

題解

#include <bits/stdc++.h>

using namespace std;
string str[10]={"zero","one","two","three","four",
                "five","six","seven","eight","nine"};
int main()
{
#ifdef ONLINE_JUDGE
#else
    freopen("1.txt", "r", stdin);
#endif
    string s;
    int sum=0;
    vector<int> v;
    cin>>s;
    for(int i=0;i<s.length();i++){
        sum+=(s[i]-'0');
    }
    if(sum==0){
        cout<<"zero"; return 0;
    }
    while(sum){
        v.push_back(sum%10);
        sum/=10;
    }
    for(int i=v.size()-1;i>=0;i--)
    {
        if(i!=v.size()-1)```
            cout<<" "<<str[v[i]];
        else cout<<str[v[i]];
    }
}
 

柳神程式碼
柳神的程式碼還是極致優雅啊~

#include <iostream>
using namespace std;
int main() {
    string a;
    cin >> a;
    int sum = 0;
    for (int i = 0; i < a.length(); i++)
        sum += (a[i] - '0');
    string s = to_string(sum);
    string arr[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    cout << arr[s[0] - '0'];
    for (int i = 1; i < s.length(); i++)
        cout << " " << arr[s[i] - '0'];
    return 0;
}