1041 Be Unique (20 分)(hash雜湊)
Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print "None" instead.
Sample Input 1:
7 5 31 5 88 67 88 17
Sample Output 1:
31
Sample Input 2:
5 888 666 666 888 888
Sample Output 2:
None
生詞
英文 | 解釋 |
---|---|
lottery | 彩票 |
題目大意:
給n個數字,按照讀入順序,哪個數字是第一個在所有數字中只出現一次的數字。如果所有數字出現都超過了一次,則輸出None
分析:
建立一個數組,儲存每個數字出現的次數,然後遍歷一遍輸入的順序看是否有出現次數為1的數字
原文連結:https://blog.csdn.net/liuchuo/article/details/52153050
題解
奇怪的是:v陣列用vector儲存後兩個測試用例會出現段錯誤。
#include <bits/stdc++.h>
using namespace std;
int v[100010],h[100010];
int main()
{
#ifdef ONLINE_JUDGE
#else
freopen("1.txt", "r", stdin);
#endif
int n;
//vector<int> v(n);
scanf("%d",&n);
for(int i=0;i<n;i++)
{
scanf("%d",&v[i]);
h[v[i]]++;
}
for(int i=0;i<n;i++){
if(h[v[i]]==1){
printf("%d\n",v[i]);
return 0;
}
}
printf("None\n");
return 0;
}
本文來自部落格園,作者:勇往直前的力量,轉載請註明原文連結:https://www.cnblogs.com/moonlight1999/p/15570127.html