1. 程式人生 > 實用技巧 >Linux運維之監控CPU和記憶體的日誌工具

Linux運維之監控CPU和記憶體的日誌工具

一、監控CPU和記憶體的日誌工具的使用

1、阿里雲提供了一個監控CPU和記憶體的指令碼,因free版本不同的原因,指令碼中的內容有做細微的修改,指令碼內容如下:

#!/bin/bash
#When the free memory very less ,this script to collect CPU/memory usage information and dmessage information. 
#Version 1.0 time:2014-3-11
#Version 2.0 time:2014-12-23
#Version 3.0 time:2020-07-12

logfile=/tmp/$0.log

check_os_release()
{
  
while true do os_release=$(grep "Red Hat Enterprise Linux Server release" /etc/issue 2>/dev/null) os_release_2=$(grep "Red Hat Enterprise Linux Server release" /etc/redhat-release 2>/dev/null) if [ "$os_release" ] && [ "$os_release_2" ] then if echo "$os_release"|grep "
release" >/dev/null 2>&1 then os_release=redhat echo "$os_release" else os_release="" echo "$os_release" fi break fi os_release=$(grep "Aliyun Linux release" /etc/issue 2>/dev/null) os_release_2=$(grep "Aliyun Linux release" /etc/aliyun-release 2>/dev/null)
if [ "$os_release" ] && [ "$os_release_2" ] then if echo "$os_release"|grep "release" >/dev/null 2>&1 then os_release=aliyun echo "$os_release" else os_release="" echo "$os_release" fi break fi os_release_2=$(grep "CentOS" /etc/*release 2>/dev/null) if [ "$os_release_2" ] then if echo "$os_release_2"|grep "release" >/dev/null 2>&1 then os_release=centos echo "$os_release" else os_release="" echo "$os_release" fi break fi os_release=$(grep -i "ubuntu" /etc/issue 2>/dev/null) os_release_2=$(grep -i "ubuntu" /etc/lsb-release 2>/dev/null) if [ "$os_release" ] && [ "$os_release_2" ] then if echo "$os_release"|grep "Ubuntu" >/dev/null 2>&1 then os_release=ubuntu echo "$os_release" else os_release="" echo "$os_release" fi break fi os_release=$(grep -i "debian" /etc/issue 2>/dev/null) os_release_2=$(grep -i "debian" /proc/version 2>/dev/null) if [ "$os_release" ] && [ "$os_release_2" ] then if echo "$os_release"|grep "Linux" >/dev/null 2>&1 then os_release=debian echo "$os_release" else os_release="" echo "$os_release" fi break fi break done } rhel_fun() { while true do #vm_mem=$(free -m|grep "buffers/cache"|awk '{print $4}') vm_mem=$(free -m|grep "Mem"|awk '{print $7}') cpu=$(top -bn2|grep "Cpu(s)"|awk '{print $8}'|awk -F'%' '{print $1}'|tail -n1) check_cpu=$(echo "$cpu <20" |bc) if [[ $vm_mem -le 100 ]] || [[ $check_cpu -eq 1 ]] then echo "======================================================" >>$logfile date >>$logfile echo "======================================================" >>$logfile echo "The memory is too less." >>$logfile free -m >>$logfile echo "=======================CPU info========================" >>$logfile (ps aux|head -1;ps aux|sort -nrk3|grep -v "RSS") >>$logfile echo "=======================Memory info=====================" >>$logfile (ps aux|head -1;ps aux|sort -nrk6|grep -v "RSS") >>$logfile date >>$logfile echo "=======================Dmesg info=====================" >>$logfile dmesg >>$logfile dmesg -c fi sleep 10 done } debian_fun() { while true do vm_mem=$(free -m|grep "buffers/cache"|awk '{print $4}') cpu=$(top -bn2|grep "Cpu(s)"|awk '{print $5}'|awk -F'%' '{print $1}'|tail -n1) check_cpu=$(echo "$cpu <20" |bc) if [[ $vm_mem -le 100 ]] || [[ $check_cpu -eq 1 ]] then echo "======================================================" >>$logfile date >>$logfile echo "======================================================" >>$logfile echo "The memory is too less." >>$logfile free -m >>$logfile echo "=======================CPU info========================" >>$logfile (ps aux|head -1;ps aux|sort -nrk3|grep -v "RSS") >>$logfile echo "=======================Memory info=====================" >>$logfile (ps aux|head -1;ps aux|sort -nrk6|grep -v "RSS") >>$logfile date >>$logfile echo "=======================Dmesg info=====================" >>$logfile dmesg >>$logfile dmesg -c fi sleep 10 done } check_os_release case "$os_release" in redhat|centos|aliyun) yum install bc -y rhel_fun ;; debian|ubuntu) apt-get install bc -y debian_fun ;; esac

2、上傳到/tmp目錄中

3、執行如下命令並後臺執行該指令碼

cd /tmp
nohup bash get_cpu_mem_info.sh &

4、該工具會在/tmp目錄下生成一個以指令碼名字命名的日誌檔案,實時記錄系統的CPU、記憶體的使用情況,等到系統異常時可以用於分析日誌。

二、監控CPU和記憶體的日誌工具的詳解

1、