android 震動和提示音的實現程式碼
阿新 • • 發佈:2020-01-07
android的訊息提示(震動和提示音),實現程式碼如下所示:
public class VibratorUtil { protected AudioManager audioManager; protected Vibrator vibrator; private Ringtone ringtone; private static final int MIN_TIME_OUT = 4000; //時間間隔 long lastNotificationTime; public VibratorUtil() { audioManager = (AudioManager) MyApp.getContext().getSystemService(Context.AUDIO_SERVICE); //此方法是由Context呼叫的 vibrator = (Vibrator) MyApp.getContext().getSystemService(Context.VIBRATOR_SERVICE); //同上 } /** * 開啟手機震動和播放系統提示鈴聲 */ public void vibrateAndPlayTone() { if (System.currentTimeMillis() - lastNotificationTime < MIN_TIME_OUT) { return; } try { lastNotificationTime = System.currentTimeMillis(); if (audioManager.getRingerMode() == AudioManager.RINGER_MODE_SILENT) { return; } long[] pattern = new long[]{0,180,80,120}; vibrator.vibrate(pattern,-1); //震動 if (ringtone == null) { Uri notificationUri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION); ringtone = RingtoneManager.getRingtone(MyApp.getContext(),notificationUri); if (ringtone == null) { return; } } if (!ringtone.isPlaying()) { ringtone.play(); //判斷手機品牌 String vendor = Build.MANUFACTURER; if (vendor != null && vendor.toLowerCase().contains("samsung")) { Thread ctlThread = new Thread() { public void run() { try { Thread.sleep(3000); if (ringtone.isPlaying()) { ringtone.stop(); } } catch (Exception e) { } } }; ctlThread.run(); } } } catch (Exception e) { e.printStackTrace(); } } }
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