[leetcode] 713. Subarray Product Less Than K
阿新 • • 發佈:2022-03-18
題目
Given an array of integers nums
and an integer k
, return the number of contiguous subarrays where the product of all the elements in the subarray is strictly less than k
.
Example 1:
Input: nums = [10,5,2,6], k = 100 Output: 8 Explanation: The 8 subarrays that have product less than 100 are: [10], [5], [2], [6], [10, 5], [5, 2], [2, 6], [5, 2, 6] Note that [10, 5, 2] is not included as the product of 100 is not strictly less than k.
Example 2:
Input: nums = [1,2,3], k = 0
Output: 0
Constraints:
1 <= nums.length <= 3 * 10^4
1 <= nums[i] <= 1000
0 <= k <= 10^6
思路
雙指標,左右指標框起來的數字需要保持積小於k,並在遍歷nums的過程中不斷地記錄數量。
程式碼
python版本:
class Solution: def numSubarrayProductLessThanK(self, nums: List[int], k: int) -> int: cnt, prod, l = 0, 1, 0 for r in range(len(nums)): prod *= nums[r] while prod >= k and l <= r: prod /= nums[l] l += 1 cnt += r-l+1 return cnt