背景：

根據 特定欄位 分組，獲取第一次和最後一次的時間，同時要求獲得最後一次的其他資訊

資料

 結果

指令碼

WITH V_All AS (
    SELECT 1 AS UserCode, '2022-05-01' AS DateTime, 'asdasd1' AS Remark
    UNION ALL
    SELECT 1 AS UserCode, '2022-05-02' AS DateTime, 'asdasd2' AS Remark
    UNION ALL
    SELECT 1 AS UserCode, '2022-05-03' AS DateTime, 'asdasd3
 
' AS Remark
    UNION ALL
    SELECT 2 AS UserCode, '2022-05-04' AS DateTime, 'asdasd4' AS Remark
    UNION ALL
    SELECT 2 AS UserCode, '2022-05-05' AS DateTime, 'asdasd5' AS Remark
    UNION ALL
    SELECT 2 AS UserCode, '2022-05-06' AS DateTime, 'asdasd6' AS Remark
    UNION ALL
    SELECT 3 AS UserCode, '
 
2022-05-07' AS DateTime, 'asdasd7' AS Remark
), V_Group as (
    SELECT UserCode, MIN(DateTime) MinDateTime, MAX(DateTime) MaxDateTime
    FROM V_All
    GROUP BY UserCode
), V_Value as (
    SELECT DISTINCT UserCode
        , FIRST_VALUE(Remark) OVER (PARTITION by UserCode ORDER BY DateTime RANGE BETWEEN
 
 UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING ) FIRST_VALUE
        , LAST_VALUE(Remark) OVER (PARTITION by UserCode ORDER BY DateTime RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING ) LAST_VALUE
    FROM V_All
)
--SELECT * FROM V_All
SELECT * 
FROM V_Group G
INNER JOIN V_Value V ON G.UserCode = V.UserCode

Reference:

https://blog.csdn.net/sfrankzhang/article/details/7161202