視訊直播技術大全、直播架構、技術原理和實現思路方案整理(轉)
阿新 • • 發佈:2022-05-17
- 利用
PEiD
開啟reverse_3.exe,無殼,32位
2.利用ida
開啟reverse_3.exe,反編譯並找到主函式
int __cdecl main_0(int argc, const char **argv, const char **envp) { size_t v3; // eax const char *v4; // eax size_t v5; // eax char v7; // [esp+0h] [ebp-188h] char v8; // [esp+0h] [ebp-188h] signed int j; // [esp+DCh] [ebp-ACh] int i; // [esp+E8h] [ebp-A0h] signed int v11; // [esp+E8h] [ebp-A0h] char Destination[108]; // [esp+F4h] [ebp-94h] BYREF char Str[28]; // [esp+160h] [ebp-28h] BYREF char v14[8]; // [esp+17Ch] [ebp-Ch] BYREF for ( i = 0; i < 100; ++i ) { if ( (unsigned int)i >= 0x64 ) j____report_rangecheckfailure(); Destination[i] = 0; } sub_41132F("please enter the flag:", v7); sub_411375("%20s", (char)Str); v3 = j_strlen(Str); v4 = (const char *)sub_4110BE(Str, v3, v14); strncpy(Destination, v4, 0x28u); v11 = j_strlen(Destination); for ( j = 0; j < v11; ++j ) Destination[j] += j; v5 = j_strlen(Destination); if ( !strncmp(Destination, Str2, v5) ) sub_41132F("rigth flag!\n", v8); else sub_41132F("wrong flag!\n", v8); return 0; }
- 程式碼分析
輸入flag經過函式sub_4110BE變換,進入這個函式看看它在幹什麼
void *__cdecl sub_411AB0(char *a1, unsigned int a2, int *a3) { int v4; // [esp+D4h] [ebp-38h] int v5; // [esp+D4h] [ebp-38h] int v6; // [esp+D4h] [ebp-38h] int v7; // [esp+D4h] [ebp-38h] int i; // [esp+E0h] [ebp-2Ch] unsigned int v9; // [esp+ECh] [ebp-20h] int v10; // [esp+ECh] [ebp-20h] int v11; // [esp+ECh] [ebp-20h] void *v12; // [esp+F8h] [ebp-14h] char *v13; // [esp+104h] [ebp-8h] if ( !a1 || !a2 ) return 0; v9 = a2 / 3; if ( (int)(a2 / 3) % 3 ) ++v9; v10 = 4 * v9; *a3 = v10; v12 = malloc(v10 + 1); if ( !v12 ) return 0; j_memset(v12, 0, v10 + 1); v13 = a1; v11 = a2; v4 = 0; while ( v11 > 0 ) { byte_41A144[2] = 0; byte_41A144[1] = 0; byte_41A144[0] = 0; for ( i = 0; i < 3 && v11 >= 1; ++i ) { byte_41A144[i] = *v13; --v11; ++v13; } if ( !i ) break; switch ( i ) { case 1: *((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2]; v5 = v4 + 1; *((_BYTE *)v12 + v5) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))]; *((_BYTE *)v12 + ++v5) = aAbcdefghijklmn[64]; *((_BYTE *)v12 + ++v5) = aAbcdefghijklmn[64]; v4 = v5 + 1; break; case 2: *((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2]; v6 = v4 + 1; *((_BYTE *)v12 + v6) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))]; *((_BYTE *)v12 + ++v6) = aAbcdefghijklmn[((byte_41A144[2] & 0xC0) >> 6) | (4 * (byte_41A144[1] & 0xF))]; *((_BYTE *)v12 + ++v6) = aAbcdefghijklmn[64]; v4 = v6 + 1; break; case 3: *((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2]; v7 = v4 + 1; *((_BYTE *)v12 + v7) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))]; *((_BYTE *)v12 + ++v7) = aAbcdefghijklmn[((byte_41A144[2] & 0xC0) >> 6) | (4 * (byte_41A144[1] & 0xF))]; *((_BYTE *)v12 + ++v7) = aAbcdefghijklmn[byte_41A144[2] & 0x3F]; v4 = v7 + 1; break; } } *((_BYTE *)v12 + v4) = 0; return v12; }
並且在可見字串中看到
所以sub_4110BE看上去像base64
再經過第27,28行的變換,Destination的每一位加上當前位數
再在第30行與Str2比較,檢視Str2
.data:0041A034 Str2 db 'e3nifIH9b_C@n@dH',0 ; DATA XREF: _main_0+142↑o
- 指令碼編寫
import base64 s = "e3nifIH9b_C@n@dH" x = "" for i in range(len(s)): x += chr(ord(s[i]) - i) print(base64.b64decode(x))
- 得到flag
flag{i_l0ve_you}
參考連結:
https://blog.csdn.net/qq_42967398/article/details/96603972