Big Number

Problem Description As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B.
To make the problem easier, I promise that B will be smaller than 100000.
Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines. Input The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file. Output For each test case, you have to ouput the result of A mod B. Sample Input 2 3 12 7 152455856554521 3250 Sample Output 2 5 1521 Author Ignatius.L 題意： 給出正整數 A 和 B，求 A mod B。 思路： 模擬除法運算即可。 例： 程式碼：

#include <set
 
>
#include <map>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <cmath>
#include <string>
#include <vector>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <sstream>
#include <iostream>
#include 
 
<algorithm>
#include <unordered_map>
#define INF 0x3f3f3f3f
#define ll long long
#define ull unsigned long long
#define fcio ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
using namespace std;

int main()
{
    string a;
    int b;
    while(cin>>a>>b)
    {
        int t=0
 
;
        for(int i=0;i<a.size();i++)
        {
            t=t*10+a[i]-'0';
            t=t%b;
        }
        cout<<t<<endl;
    }
}