實際發表時間：2020-03-28

\(Python\)打表！！！

這題看上去跟\(P2841\)差不多
可以用那題的程式打表
因為\(\mathcal{P2841}\)要高精，所以我用\(\mathfrak{Python}\)打表（得到數最小）
\(\qquad \qquad \qquad \quad\)這是\(\mathcal{python}\)↝
打表思路：二進位制列舉，因為數碼只有0和1
程式碼如下：

for n in range(1, 201): #前閉後開區間
    p = 1
    s = '1'
    while int(s) % n != 0: #二進位制列舉
        s = bin(p)
        s = s[2:len(s)]
        p += 1
    print(s,end=',')

 

然後...

#include<bits/stdc++.h>
using namespace std;
int x;
long long a[205]={0,1,10,111,100,10,1110,1001,1000,111111111,10,11,11100,1001,10010,1110,10000,11101,1111111110,11001,100,10101,110,110101,111000,100,10010,1101111111,100100,1101101,1110,111011,100000,111111,111010,10010,11111111100,111,110010,10101,1000,11111,101010,1101101,1100,1111111110,1101010,10011,1110000,1100001,100,100011,100100,100011,11011111110,110,1001000,11001,11011010,11011111,11100,100101,1110110,1111011111,1000000,10010,1111110,1101011,1110100,10000101,10010,10011,111111111000,10001,1110,11100,1100100,1001,101010,10010011,10000,1111111101,111110,101011,1010100,111010,11011010,11010111,11000,11010101,1111111110,1001,11010100,10000011,100110,110010,11100000,11100001,11000010,111111111111111111,100,101,1000110,11100001,1001000,101010,1000110,100010011,110111111100,1001010111,110,111,10010000,1011011,110010,1101010,110110100,10101111111,110111110,100111011,111000,11011,1001010,10001100111,11101100,1000,11110111110,11010011,10000000,100100001,10010,101001,11111100,11101111,11010110,11011111110,11101000,10001,100001010,110110101,100100,10011,100110,1001,1111111110000,11011010,100010,1100001,11100,110111,11100,1110001,11001000,10111110111,10010,1110110,1010100,10101101011,100100110,100011,100000,11101111,11111111010,1010111,1111100,1111110,1010110,11111011,10101000,10111101,111010,1111011111,110110100,1011001101,110101110,100100,110000,100101111,110101010,11010111,11111111100,1001111,10010,100101,110101000,1110,100000110,1001011,1001100,1010111010111,110010,11101111,111000000,11001,111000010,101010,110000100,1101000101,1111111111111111110,111000011,1000};
int main()
{
	ios::sync_with_stdio(false);
	while(cin>>x&&x)cout<<a[x]<<endl;
	return 0;
}