#256 (Div. 2)C. Painting Fence
阿新 • • 發佈:2017-06-21
using paint its fence int () scanf 我們 include
題意:給出籬笆的高度,寬度都是1,我們用寬度為1的刷子刷,只能橫著或者豎著刷,連續的,問最少多少次全刷完
思路:我們可以全部豎著刷,N次,然後我們如果橫著的話就是連續的非0數列中最短的和這個連續的數列都豎著刷比較,DFS
1 #include<bits/stdc++.h> 2 using namespace std; 3 const int N=5002; 4 int a[N]; 5 6 int n; 7 8 int dfs(int l,int r){ 9 int Min=1e9+7; 10 int sum=0; 11 if(l>r) return0; 12 for(int i=l;i<=r;i++){ 13 Min=min(Min,a[i]); 14 } 15 for(int i=l;i<=r;i++) 16 a[i]-=Min; 17 sum+=Min; 18 // cout<<l<<" "<<r<<" "<<sum<<endl; 19 int ll=l; 20 for(int i=l;i<=r;i++){ 21 if(a[i]==0){ 22 sum+=min(i-ll,dfs(ll,i-1)); 23 24 ll=i+1; 25 } 26 } 27 if(ll<=r){ 28 sum+=min(r-ll+1,dfs(ll,r)); 29 } 30 return sum; 31 } 32 int main(){ 33 scanf("%d",&n); 34 for(int i=1;i<=n;i++) scanf("%d",&a[i]); 35 cout<<min(n,dfs(1,n))<<endl;; 36 37 }
#256 (Div. 2)C. Painting Fence