大數相加
#include<iostream>
#include<string.h>
using namespace std;
int main()
{
char a[1100],b[1100];
int t,lena,lenb,k,y,i,j;
cin>>t;
for (int m=1;m<=t;m++)
{
int c[1200]={0};
cout << "Case " << m << ":" << endl;
cin>>a>>b;
k=0;
lena=strlen(a);
lenb=strlen(b);
cout << a << " + " << b << " = " ;
for (i=lena-1,j=lenb-1;i>=0&&j>=0;i--,j--)
{
y=a[i]-‘0‘+b[j]-‘0‘;
if (y+c[k]>=10)
{
c[k+1]++;
c[k]+=y-10;
}
else
c[k]=c[k]+y;
k++;
}
if (k<lena)
{
for (int x=i;x>=0;x--)
{
c[k]+=a[x]-‘0‘;
k++;
}
}
else if (k<lenb)
{
for (int x=j;x>=0;x--)
{
c[k]+=b[x]-‘0‘;
k++;
}
}
else if (c[k]!=0)
k++;
for (int z=k-1;z>=0;z--)
cout << c[z] ;
cout << endl;
if (m!=t)
cout << endl ;
}
return 0;
}
大數相加