Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0
  and 1.
• The length of input array is a positive integer and will not exceed 10,000

最大的連續1的個數，遞推一下

class Solution {
public:
    int findMaxConsecutiveOnes(vector<int>& nums) {
        int ans ;
        int dp1 = 0,dp2 = 0;
        dp1 = (nums[0] == 1);
        ans = dp1;
        for (int
 
 i = 1; i < nums.size(); ++i) {
            if (nums[i] == 1) {
                if (nums[i - 1] == 1) dp2 = dp1 + 1;
                else dp2 = 1;
            }
            ans = max(dp2, ans);
            dp1 = dp2;
        }
        return ans;
    }
};

leetcode 485. Max Consecutive Ones