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bzoj3709: [PA2014]Bohater(貪心)

algorithm tchar read 技術 blog put close define play

  貪心...

  可以回血的按d[i]升序防止死掉

  不能回血的按a[i]降序,因為只考慮d我們要扣除的血量是一定的,為了不死顯然回血多的放前面更好

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#include<iostream>
#include<cstring>
#include<cstdlib>
#include<cstdio> 
#include<algorithm>
#define ll long long 
using namespace std;
const int maxn=500010,inf=1e9;
struct poi{ll t,d,pos;}a[maxn],b[maxn];
ll n,m,x,y,z,tot,cnt1,cnt2;
void read(ll &k) { int f=1;k=0;char c=getchar(); while(c<0||c>9)c==-&&(f=-1),c=getchar(); while(c<=9&&c>=0)k=k*10+c-0,c=getchar(); k*=f; } bool cmp1(poi a,poi b){return a.d<b.d;} bool cmp2(poi a,poi b){return a.t>b.t;} int main() { read(n);read(z);
for(int i=1;i<=n;i++) { read(x);read(y); if(x<=y)a[++cnt1].d=x,a[cnt1].t=y,a[cnt1].pos=i; else b[++cnt2].d=x,b[cnt2].t=y,b[cnt2].pos=i; } sort(a+1,a+1+cnt1,cmp1); sort(b+1,b+1+cnt2,cmp2); for(int i=1;i<=cnt1;i++) { z-=a[i].d;
if(z<=0)return puts("NIE"),0; z+=a[i].t; } for(int i=1;i<=cnt2;i++) { z-=b[i].d; if(z<=0)return puts("NIE"),0; z+=b[i].t; } puts("TAK"); for(int i=1;i<=cnt1;i++)printf("%lld ",a[i].pos); for(int i=1;i<=cnt2;i++)printf("%lld ",b[i].pos); return 0; }
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bzoj3709: [PA2014]Bohater(貪心)